Graphing the inequalities
y ≥ 0 are the points above the x-axis including the points along the x-axis
y < x are the points below the line y = x
x + y < 6 are the points below the line x + y = 6
The solution to this is the region bounded by the lines connecting the points
(0, 0)
(0, 6)
(3, 3)
Answer: C
Step-by-step explanation:
Standard form for multi-variable expession( quadratic, trinomial, polynomial, etc) are represented by something like this.
ax^2+ bx+c, which means the stating term is the degree or exponet with the highest number then as we go right the degree go smaller.
So that means 5x^4 will be the starting term so a and b are ruled out. The next term will be x squared o x^2 so the only answer that has it second is C
Answer:
The required line can be found by substituting the slope and the given point in the slope intercept form of a line and is given by y=mx+c, where m is the slope and c is the y intercept.
Step-by-step explanation:
- In the given question, it is given that a linear function passes through a given point.
- It is required to find a line parallel to the function.
- When two functions are parallel, their slopes are equal.
- Thus, substitute the slope and the given point in the slope intercept form of a line and is given by y=mx+c, where m is the slope and c is the y intercept.
Answer:
3.
Step-by-step explanation:
From the question given above, the following data were obtained:
Logᵦ 8 = 3
Logᵦ 0.5 = – 1
Logᵦ 4B =?
Next, we shall determine the value of B. This can be obtained as follow:
Logᵦ 8 = 3
8 = B³
Take the cube root of both side.
B = 3√8
B = 2
Finally, we shall determine the value of Logᵦ 4B. This can be obtained as follow:
Logᵦ 4B =
B = 2
Logᵦ (4×2) = Logᵦ 8
Recall from the question given:
Logᵦ 8 = 3
Therefore,
Logᵦ 4B = Logᵦ 8 = 3
Thus, the value of Logᵦ 4B is 3.
