Answer: choice A) 7017
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Work Shown:
The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7
The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7
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The 1000th term corresponds to n = 1000
Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify
a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
Answer:
I think the answer is D
Step-by-step explanation:
SOHCAHTOA
sin- Opposite and hypotenuses
Cos- Adjacent and Hypothesis
Tan- Opposite and adjacent
DE is opposite and DF is hypotenuses
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
(a) 0.2707
(b) 0.8576
Step-by-step explanation:
