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3 years ago

Solve for x: 4 = (-8) +3x. Will you please help?

Mathematics

2 answers:

Zanzabum3 years ago

8 0

8 + 4 = 3x
12 = 3x
divide both sides by 3
x= 4

Artist 52 [7]3 years ago

7 0

X = 4 (i need 20 characters excuse this)

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A number decreased by the sum of the number and four

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3 years ago

Imagine we are throwing a five-sided die 50 times. on average out of these 50 throws how often would the five-sided die show an

lakkis [162]

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4 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

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with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

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$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

I’ve tried to work this out but I can’t get it figured out. Can someone help me

Bas_tet [7]

G(2) = -4(2) = -8
f(g(2)) = (-8)^2 = 64

answer
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3 years ago

Find the area of the following rectangle,

lesya692 [45]

Answer:

55/72 feet squared

Step-by-step explanation:

The area of a rectangle is Length x Height, or Width x Height.

Here, we have a width of 5/6 feet and a height of 11/12 feet.

We multiple 5/6 and 11/12 to get 55/72 feet squared.

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3 years ago