First 1/5 is equivalent to 20% so to get 20% of both of them multiply by .2. so 400×.2=80 and 90×.2=18
Answer:
59.15 in^2
Step-by-step explanation:
Using Heron's formula
semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4
Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2
Answer:
See below ~
Step-by-step explanation:
<u>Question 1</u>
⇒ -7x - (8x + 16) = -1
⇒ -7x - 8x - 16 = -1
⇒ -15x = 15
⇒ x = -1
⇒ y = 8(-1) + 16 = 8
⇒ Solution = <u>(-1, 8)</u>
<u></u>
<u>Question 2</u>
⇒ 3x + 4(-3x - 18) = 0
⇒ 3x - 12x - 72 = 0
⇒ -9x = 72
⇒ x = -8
⇒ y = -3(-8) - 18 = 6
⇒ Solution = <u>(-8, 6)</u>
<u>Question 3</u> (not clear)
<u>Question 4</u>
⇒ -8x - 7(6x) = 0
⇒ -8x - 42x = 0
⇒ -50x = 0
⇒ x = 0
⇒ y = 6(0) = 0
⇒ Solution = <u>(0, 0)</u>
<u>Question 8</u>
- 2x - 6y = -14
- y = -5x - 19
⇒ 2x - 6(-5x - 19) = -14
⇒ 2x + 30x + 114 = -14
⇒ 32x = -128
⇒ x = -4
⇒ y = -5(-4) - 19 = 1
⇒ Solution = <u>(-4, 1)</u>
T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
