By Pythagorean theorem
x²+GF²=EF² ( where G is the point of intersection of perpendicular lines)
now, GF=1/2 EF= 12
x²+12²=24²
x²=24²-12²
x²=432
x=√432
x=12√3
x≈20.78
Find the intersection of the following sets.<br><br>a= 1,2,3,4,5,6,7,8 b= 2,4,6,8,10<br>
Neporo4naja [7]
{2,4,6,8}
Intersection means common elements in both sets
That is correct. The log3 stays the same and the numerator goes first and then the denominator goes second. When it’s a fraction like that one, the standard form would be subtraction.
Given that triangle <span>STU
is reflected once to map onto
triangle S'T'U'.
Given that triangle STU has
vertices S(8, 6), T(2, 2), U(5, 1).
If vertex T' is at
(2, −2), this means that triangle STU is refrected across the x-axis.
A refrection across the x-axis results in an image that has the same x-value as the pre-image but a y-value that has the opposite sign of the y-value of the pre image.
Thus, a point, say (x, y), refrected over the x-axis will result in an image with coordinate (x, -y)
Therefore, given that the coordinate of S is (8, 6), then the coordinates of vertex S'</span> is (8, -6).
