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lawyer [7]
3 years ago
8

Please help me I'm sooooo stressed!!!! plz help

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

with what you didnt say what you needed help with

Step-by-step explanation:

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(x-4)/(x+5) less than or equal to 0<br> solve
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This is the solution

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3 years ago
What Is the perfect square of 9x-1
Maksim231197 [3]

(9x - 1)²  =  <em>81x² - 18x + 1</em>


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3 years ago
Jeffrey went to the Outlets to buy some clothes. He bought a pair of pants for $59.99 and a nice shirt for $32.00. He read a sig
atroni [7]

Answer: 64.39 dollars

==========================================================

Explanation:

Before the discount, he would spend 59.99+32 = 91.99 dollars. This is before sales tax is added.

However, he gets 30% off, so he saves 0.30*91.99 = 27.597 = 27.60 dollars.

Meaning that he actually spends 91.99 - 27.60 = 64.39 dollars

--------------

As a shortcut, we can multiply 91.99 by 0.70 to get 64.393 which rounds to 64.39

The 0.70 is due to the fact that if he saves 30%, then he still has to pay the remaining 70%

Keep in mind that sales tax would need to be added on; however, your teacher doesn't mention the sales tax rate.

5 0
3 years ago
You would more likely give your friends a number of blocks to go east and then a number of blocks to go north. what would these
AnnyKZ [126]

the answer is 2 , 0

3 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!
elena55 [62]

h(x)=(f\circ g)(x)\\\\h(x)=\sqrt[3]{x+3};\ f(x)=\sqrt[3]{x+2}\\\\h(x)=\sqrt[3]{x+1+2}=\sqrt[3]{(x+1)+2}=\sqrt[3]{g(x)+2}\to \boxed{g(x)=x+1}

-----------------------------------------------------------------------------------------------

f(x)=2x;\ g(x)=2x-1;\ h(x)=\sqrt{x}\\\\(f\circ g\circ h)(9)=?\\\\h(9)=\sqrt9=3\\\\(g\circ h)(9)=g(3)=2(3)-1=6-1=5\\\\(f\circ g\circ h)(9)=f(5)=2(5)=10\\------------------------------\\other\ method:\\\\(f\circ g\circ h)(x)=2(2\sqrt{x}-1)=4\sqrt{x}-2\\\\(f\circ g\circ h)(9)=4\sqrt9-2=4(3)-2=12-2=10

-------------------------------------------------------------------------------------------------

f(x)=4x+1;\ g(x)=x^2-5\\\\(f\circ g)(4)=?\\\\g(4)=4^2-5=16-5=11\\(f\circ g)(4)=f(11)=4(11)+1=44+1=45\\----------------------------------\\other\ method:\\\\(f\circ g)(x)=4(x^2-5)+1=4x^2-20+1=4x^2-19\\\\(f\circ g)(4)=4(4)^2-19=4(16)-19=64-19=45


8 0
3 years ago
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