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2 years ago

Ive been on here for 20 minutes trying to do this but i keep getting stuck

Mathematics

1 answer:

Luden [163]2 years ago

4 0

Answer:

c=175

b=2050

g=18.44

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Please put in order smallest to largest.

yaroslaw [1]

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3 years ago

Stacy and Travis are rock climbing. Stacy's rope is 4 feet shorter than 3 times the length of Travis' rope. Stacy's rope is 23 f

abruzzese [7]

First, take off 4 feet of Stacy's rope, which is 19. (23-4=19). Then, divide 19 by 3. It should equal 6.3...

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

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$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

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which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

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3 years ago

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valkas [14]

Answer:

Step-by-step explanation:

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divide both sides by 8

x=6

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3 years ago

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Gnoma [55]

Answer:

14x^3+39x^2+18x+20

Step-by-step explanation:

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3 years ago

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