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Sliva [168]
3 years ago
10

Can someone help me with these and please show work and explain because I don’t really get it :(

Mathematics
1 answer:
stich3 [128]3 years ago
7 0
The acronym: SOH CAH TOA
Stands for;
Sin(x) = Opposite / Hypotenuse
Cos(x) = Adjacent / Hypotenuse
Tan(x) = Opposite / Adjacent

What you have written on the triangle. The angle is what goes inside the trig functions (Sine, Cosine, Tangent). The side opposite of the 36° angle is MP. The Hypotenuse of the triangle (always the longest side) is side PN. The Adjacent side to the 36° angle is given to be 28.

Use trig functions containing the given Adjacent side to solve for the missing sides Opposite, P and Hypotenuse, H .

Opposite side (calling it "P")
Tan(36°) = P / 28
multiply by 28 on both sides
28 × Tan(36°) = P
20.34 = P

Hypotenuse of the triangle (H)
Cos(36°) = 28 / H
Cross multiply
H = 28 / Cos(36°)
H = 34.61

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MArishka [77]

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7 0
3 years ago
The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
gtnhenbr [62]

Answer:

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Step-by-step explanation:

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Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

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8 0
3 years ago
Read 2 more answers
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leva [86]

Answer:

Here,

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We know that cosD= b/h

=21/75

=7/25

7 0
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