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Dahasolnce [82]
3 years ago
12

Suppose the test scores of students in a class are normally distributed with a mean of 85 and a standard deviation of 4. What is

the z-score for a student that scored 79 on a test
A. -4
B. -1.5
C. 1.5
D. 4
Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Converting it to z, we can use the formula of z-score:

z-score = \frac{x-\mu}{\sigma}

Where

x is the value we are checking for (here, x = 79)

\mu  is the mean, which is 85

\sigma is the standard deviation, which is 4 now

<em>Let's plug the information into the formula and solve for the answer:</em>

<em>\frac{x-\mu}{\sigma}\\\frac{79-85}{4}\\-\frac{6}{4}\\-1.5</em>

<em />

<em>B is the correct answer.</em>

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Let f(x)= lxl-3 Write a function g whose graph is a translation 5 units down of the graph of f.
soldier1979 [14.2K]

If the function "f(x) = lxl-3" were translated five units down the graph, g(x) would be lxl-8.

We must be familiar with function transformation and different forms of transformation in order to properly understand the question. When a function is transformed, the graph's curve either "moves to the left/right/up/down," "expands or compresses," or "reflects" to create a new function. For instance, by simply pushing the graph of the function g(x) = x2 up by 7 units, the graph of the function f(x) = x2 + 7 is generated. It is advantageous to convert a function since it saves us from having to create a new function from begin. Function transformations typically fall into one of three categories: 1. 2nd translation 3. dilation Reflection

The given query is about Translation of Function. To create a new function, translation moves the curve up or down and modifies its position. Translation comes in two flavours. Vertical and horizontal translation.

When the curve changes, "the function" shifts upward or downward. By doing this, a function of the form y = f(x) is transformed into f(x) ± k, where k stands for the vertical translation. In this case, the function moves up by k units if k > 0.

The function goes down by 'k' units if k < 0.

The curve in the given problem goes down by 5 units, so k = 5. Which is a vertical translation scenario. Consequently, y = f(x) becomes f(x) - k = g(x) and g(x) = f(x) - k = lxl-3 -5 = lxl - 8.

Therefore the new function after translation is g(x) =  lxl - 8.

Learn more about function and types of transformation such as translation, dilation etc here

brainly.com/question/26092237

#SPJ9

4 0
1 year ago
Find the area of a rectangle that has a length of 5x+1 and a width of 2x+3
pantera1 [17]
I could be wrong, but I'm pretty sure here the answer would be 10x^2 + 17x +3 would be the area since you have to multiply length and width. since these are expressions with no answers and no other numbers, we can't find x.

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Solve. x 2 /7
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The answer is D I think

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An arithmetic sequence is represented by the explicit formula A(n) = 2 +(n − 1)(− 5)
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A new​ phone-answering system installed by a certain utility company is capable of handling twelve calls every 5 minutes. Prior
SVEN [57.7K]

Answer:

A. P(x>12 in 5 minutes)=0.0201

Step-by-step explanation:

Because we are working with a Poisson Distribution of probability, we need to get all the data needed. In a Poisson distribution is needed a constant called λ that symbolizes the mean data (6 calls) per unit of time (5 minutes), for this distribution λ=6/5.

Poisson probabilities work like this:

P(x=y\ 'in\ z\ unit\ of\ time')= \frac{e^{-z\lambda}(z\lambda)^{y}}{y!}

Remember y has to be an integer and the units of z must be the same unit of time used in λ. Now we are ready to solve this problem

A. The question is asking for the probability that in 5 minutes appear more calls than the phone-answering machine could answer (i.e P(x>12 in 5 minutes)). Because there are infinite numbers greater than 12, we are using this property of probabilities that´ll help us simplify the problem:

P(x>12 in 5 minutes)= 1 - P(x≤12 in 5 minutes)

Now we can use the following:

P(x\geq12\ in\ 5\ minutes)=P(x=0\ in\ 5\ min)+P(x=1\ in\ 5\ min)+...P(x=12\ in\ 5\ min)

P(x\geq12\ in\ 5\ minutes)=\sum_{n=0}^{\infty}P(x=n\ in\ 5\min)

P(x\geq12\ in\ 5\ minutes)=\sum_{n=0}^{\infty}\frac{e^{-6}6^{n}}{n!}

And you can find P(x=n in 5 minutes) for every n using a calculator or a computer, and finally add them to get

P(x≤12 in 5 minutes)= 0.9799

P(x>12 in 5 minutes)= 1-0.9799

This will be our answer

P(x>12 in 5 minutes)= 0.0201

8 0
3 years ago
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