What is the value of y when y=10 and 1/4x+10-2y=3y

SIMPLIFY THE FOLLOWING EXPRESSION: given that s ≠ 0, and write your answer using only positive exponents. Thanks in advance!!!

Umnica [9.8K]

Answer:

4s¹²/(9t⁴)

Step-by-step explanation:

Solving in steps:

(3s⁻⁴t⁷s⁰)⁻²(-2s²t⁵)² =
3⁻²s⁻⁴ˣ⁻²t⁷ˣ⁻²(-2)²s²ˣ²t⁵ˣ² =
1/9×s⁸t⁻¹⁴(4)s⁴t¹⁰ =
4/9 ×s⁸⁺⁴t⁻¹⁴⁺¹⁰ =
4/9 ×s¹²t⁻⁴=
4s¹²/(9t⁴)

3 0

3 years ago

Discuss the steps that you used to create your tangent line. What was the most important step?

Otrada [13]

Answer:

I can't see the question

4 0

2 years ago

What is the square root of 3 multiplied by 1/2 in the simplest radical form?

steposvetlana [31]

Answer:

usbqjqnamallqnbajabqjqnqkqlqlqllqqlqoqoqnajajhchhsgavbsujwhwjwjqqbq.

hshsjwhwjwjuwubwbwwuwhquuwqjqjqkqbqv pangit mo potang ina mo bulok wlang silbe wag kana mag ajabajajajqkqjbqiqiq

8 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Sally is baking cupcakes for her birthday party.

Katena32 [7]

Answer:

Where's the rest of the question?

5 0

2 years ago