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77julia77 [94]
3 years ago
11

There are 7 yellow, 5 green, and 3 blue party hats in a bag. you randomly choose a yellow party hat and put it on. then your fri

end randomly chooses a yellow party hat. what is the probability of both of you choosing a yellow party hat?
Mathematics
1 answer:
ehidna [41]3 years ago
8 0
7 yellow, 5 green, 3 blue...total of 15

P(yellow party hat) = 7/15
do not replace
P(yellow hat) = 6/14

P(both) = 7/15 * 6/14 = 42/210 which reduces to 1/5 or 0.2 or 20%
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The temperature was 6° C.<br> By how much has it fallen if it is now -5° C?
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Read 2 more answers
Simplify. 3725−−√−2825−−√+6325−−√ 457√ 7√ 257√ 857√
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Answer:

Option A.

Step-by-step explanation:

Consider the given problem is

3\sqrt{\frac{7}{25}}-\sqrt{\frac{28}{25}}+\sqrt{\frac{63}{25}}

Using the properties of radical expressions we get

3\cdot \frac{\sqrt{7}}{\sqrt{25}}-\frac{\sqrt{28}}{\sqrt{25}}+\frac{\sqrt{63}}{\sqrt{25}}             [\because \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}]

3\cdot \frac{\sqrt{7}}{\sqrt{25}}-\frac{\sqrt{4}\sqrt{7}}{\sqrt{25}}+\frac{\sqrt{9}\sqrt{7}}{\sqrt{25}}              [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

3\cdot \frac{\sqrt{7}}{5}-\frac{2\sqrt{7}}{5}+\frac{3\sqrt{7}}{5}

Taking out common factors.

\frac{\sqrt{7}}{5}(3-2+3)

\frac{\sqrt{7}}{5}(4)

\frac{4\sqrt{7}}{5}

The simplified form of given expression is \frac{4}{5}\sqrt{7}

Therefore, the correct option is A.

4 0
3 years ago
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