All categories

4 years ago

$119.50 skateboard; 20% off; 7% tax

Mathematics

2 answers:

lapo4ka [179]4 years ago

5 0

119.50 times .80= 95.6. 95.6 times 1.07= $102.29.

andreev551 [17]4 years ago

4 0

I think that is the answer to your question if not I'll figure it out
Question

You might be interested in

salma and ahlam are making cat toys from yarn. salma need 1/2 yard for the toy she is making. ahlam needs 3 times as much yarn a

OLga [1]

Answer: 1 1/2 yards of yarn

Step-by-step explanation: For this problem, we will simply be multiply 1/2 yard by 3 to get the amount of yard that Ahlam will need.

1/2 x 3/1 = 3/2 or 1 1/2 yards of yarn. Basically you multiply the top of the fractions first (1 x 3) = 3 Then, you multiply the bottom of the fractions second (2 x 1) = 2 (3/2 or 1 1/2)

5 0

3 years ago

Read 2 more answers

What is the value of d to the nearest tenth?

irina1246 [14]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

PA = 22

PB = 22+40=62

PC = 26

PD = 26+d

As we know the rule of tangents :

PA.PB=PC.PD

$22\times 62=26(26+d)\\\\1364=676+26d\\\\1364-676=26d\\\\688=26d\\\\\dfrac{688}{26}=d\\\\d=26.46\\\\d=26.5$

Hence, First option is correct.

7 0

3 years ago

Read 2 more answers

I need help pleaseeee

Scrat [10]

I beleive the answer is C

5 0

3 years ago

Read 2 more answers

Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p

vova2212 [387]

Answer:

Regression function: $y=1986.406+0.0059x$

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function $y=b_0+b_1x_1$ by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

$b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}$

We start calculating the average of x and y

$\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005$

The sample covariance can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250$

The variance of x can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000$

Now we can calculate the parameters of the regression model

$b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485 \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413$

The function then become:

$y=1986.406+0.0059x$

With this linear equation we can predict when the population will reach 14,000:

$y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523$

6 0

3 years ago

By the black sheep has seven pounds of wolf is he separated into three bags together

dezoksy [38]

7 divided by 3 is 3.5
half of 6 is 3 and you can't evenly divided 7 by 2 so you would say that
3.5
+ 3.5
__________
7

5 0

3 years ago