Answer:
What class is this for
Step-by-step explanation:
Bc I might know this
Answer:
Step-by-step explanation:
One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...
d = b² -4ac
When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.
We can find the discriminant values to be ...
A: d = 2² -4(1)(4) = -12 . . . . no real zeros
B: d = 0² -4(3)(-5) = 60 . . . two real zeros
C: d = 8² -4(-2)(0) = 64 . . . two real zeros
D: d = 10² -4(1)(26) = -4 . . .no real zeros
Expressions A and D have no real zeros.
_____
<em>Comment on the question</em>
You are given an <em>expression</em>, not an <em>equation</em>. There is no equal sign. Hence, we cannot talk about <em>solutions</em>. We can only talk about <em>zeros</em>, values of x that make the expression have a value of zero.
Answer:
<h2>
b) y = -3x - 7</h2>
Step-by-step explanation:
3x + y = 5 {subtract 3x from both sides}
y = -3x + 5 ← slope-intercept form
y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂
{Two lines are parallel if their slopes are equal}
y = -3x + 5 ⇒ m₁ = -3 ⇒ m₂ = -3
(-1, -4) ⇒ x₁ = -1, y₁ = -4
The point-slope form:
y - (-4) = -3(x - (-1))
y + 4 = -3(x + 1)
y + 4 = -3x - 3 {subtact 4 from both sides}
<h3>
<u>y = -3x - 7 </u><u> ← slope-intercept form</u></h3>
Answer:
It's four.
Step-by-step explanation:
Doesn't require an explanation buuut.... Imagine you have two apples, and a friend gives you two more, you then have four apples.
