If two similar triangles have side lengths 3cm and 7cm then we can determine that the scale factor for the lengths is: 7/3
Now, we have to work out the area scale factor !
This is simple, since area is given in cm² then all we have to do is square our original scale factor!
So,
7/3² = 49/9
So, we can say that the ratio of the area would be:
x : 49/9x
Hope this helps! <3
Answer:
All you need to do is to calculate the perimeter of the circle since you already had the diameter
Base on the picture, the perimeter should be:
C = d * π = 64 * 3.14 = 200.96 (m)
Answer:
Step-by-step explanation:
Given
See attachment for figure
Required
The scale factor (k)
Since point C is the center of dilation, the scale factor (k) is calculated using:
So, we have:
Salut. BC²=AC²-AB² , BC=√((10)²-(8)²) , BC=√(100-64) , BC=√36 , BC=6cm. J'espere t,avoir aidé
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.