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3 years ago

Solve x 2 - x - 5/2 = 0 using the quadratic formula.

Mathematics

2 answers:

rewona [7]3 years ago

6 0

Answer:

your answer would be: x=1±√11 all divided by 2

Hope this helps

~QueenSupreme AKA Trinity

azamat3 years ago

6 0

Answer: $\bold{\dfrac{1\pm \sqrt{11}}{2}}$

<u>Step-by-step explanation:</u>

$x^2-x-\frac{5}{2}=0\quad \text{multiply by 2 to get:}\\\\2x^2-2x-5=0\quad \rightarrow \quad a=2,\ b=-2,\ c=-5\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(2)(-5)}}{2(2)}\\\\\\.\ =\dfrac{2\pm \sqrt{40}}{2(2)}\\\\\\.\ =\dfrac{2\pm \sqrt{44}}{2(2)}\\\\\\.\ =\dfrac{2\pm 2\sqrt{11}}{2(2)}\\\\\\.\ =\boxed{\dfrac{1\pm \sqrt{11}}{2}}$

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Two lines or equations are described in each part. Decide whether each system has one solution, no solution, or infinitely many

olga55 [171]

To get the solution of a set of equations means to get a point that satisfies both equations.

Part (1):
The first line has a rate of change of 7, this means that slope of first line is 7
The second line has a rate of change of -7, this means that slope of second line is -7
Since the slope of the first line = - slope of the second line, then these two lines are definitely perpendicular to each other.
Two perpendicular lines will meet only in one point. This means that one point only will satisfy both equations (check the image showing perpendicular lines attached below)
Therefore, only one solution exists in this case

Part (2):
The first given equation is:
2x + 3y = 5.5
The second given equation is:
4x + 6y = 11
If we simplified the second equation we will get: 2x + 3y = 5.5 which is exactly similar to the first equation.
This means that the two given equations represent the same line.
Therefore, we have infinite number of solutions

Part (3):
We are given that the two lines are parallel. This means that the two lines are moving the same path side by side. Two parallel lines can never intersect. This means that no point can satisfy both equations (check the image showing parallel lines attached below).
Therefore, we have no solutions for this case.

7 0

3 years ago

Read 2 more answers

Meg's treasure map is on a grid. The map tells Meg to dig a hole five units from point N. Which point represents where Meg could

Nezavi [6.7K]

Answer:

(6,5)

Step-by-step explanation:

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3 years ago

Find the distance between each pair of points. round your answer to the nearest tenth.

goldenfox [79]

Answer:

5.4

Step-by-step explanation:

To find the distance between each pair of points, we use the distance formula, which is:

d = $\sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2 }$

So we have

$x_{1} = 2\\ x_{2} = 4\\y_{1} = 8\\y_{2}=3$

When we plug in the values into the formula we get:

d = $\sqrt{(4-2)^2 + (3-8)^2}$

d = $\sqrt{4 + 25}\\ =\sqrt{29}\\ =5.4$

3 0

3 years ago

Read 2 more answers

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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3 years ago

Mr.Atkinson has 5 lb of dry fish food. He will put an equal amount of food into 3

Helen [10]

Answer:

5 times 3 =15lb

Step-by-step explanation:

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3 years ago