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brilliants [131]

2 years ago

13

The Waters family budget a maximum amount of $150 per week for groceries. Mr. Waters already spent $40. Write and solve an inequ

ality to determine how much more the Waters family can spend on groceries.

1 answer:

ivann1987 [24]2 years ago

8 0

150-40 less than or equal to $110 -

They can spend less than or equal to $110

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|6-27| how the answer this question

sweet [91]

Answer:

First notice that they’re asking for the absolute value of the equation.

The absolute value is how far that number is from 0.

Basically it’s the number without a negative sign.

ok so 6-27 = -21

The product for 6-27 (21) is 21 spaces away from 0.

|6-27| = 21

21 is the answer to your question.

Hope this helped and pls mark me brainliest if it did :)

7 0

2 years ago

Read 2 more answers

Problem<br> 1<br> + 10x + 13 = 4

lutik1710 [3]

Answer:

$x = -1$

Step-by-step explanation:

Equation: $1+10x+13=4$

Step 1: Balance both parts of the equation.

$1+10x+13=4$

$(10x)+(1+13)=4$

$10x+14=4$

$10x+14=4$

Step 2: Reduce 14 from both parts of the equation.

$10x+14-14=4-14$

$10x= -10$

Step 3: Split both sides by 10, because $\mathrn {10x = -10}$ .

$\frac{10x}{10} = \frac{-10}{10}$

$10 / -10 = -1$

Therefore, x = -1.

6 0

2 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

If 2x-1 is a factor of 16x^4-24x^3+2x+f find f

olganol [36]

Answer: HERE HOPE IT HELPS

Step-by-step explanation:

4 0

3 years ago

Plz plz answer this 10pts

NNADVOKAT [17]

Answer:

PART A

$4.25×2.9
$12.325

PART B

cost of milk chocolate=$5.15×1.6
$8.24

total cost =12.325+8.24

$20.565

hope it helps

<h3>stay safe healthy and happy.</h3>

6 0

2 years ago

Read 2 more answers