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3 years ago

Please help???????????

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

5 0

Answer:

x - $\sqrt{7}$

Step-by-step explanation:

A polynomial has the form

first term is the term of highest degree followed by term of second etc.

note that x = $x^{1}$ ← degree 1

x - $\sqrt{7}$

fits this description and is a polynomial of degree 1

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He nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports t

kiruha [24]

This problem is better understood with a given figure. Assuming that the flight is in a perfect northwest direction such that the angle is 45°, therefore I believe I have the correct figure to simulate the situation (see attached).

Now we are asked to find for the value of the hypotenuse (flight speed) given the angle and the side opposite to the angle. In this case, we use the sin function:

sin θ = opposite side / hypotenuse

sin 45 = 68 miles per hr / flight

flight = 68 miles per hr / sin 45

<span>flight = 96.17 miles per hr</span>

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3 years ago

Which congruence theorems can be used to prove △ABR ≅ △ACR? Check all that apply. HL SAS SSS ASA AAS

Verizon [17]

HL (It's a right triangle and the hypotenuse and leg are congruent. This can also be thought of as SAS.)

SAS (Side angle side. All congruent.)

SSS (Line AR is shared by both triangles. A line is always congruent on itself. The other two are self explanatory.)

ASA and AAS cannot be used because we can only confidently confirm one angle of each triangle.

5 0

3 years ago

Read 2 more answers

Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?

mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.

From the figure in the attachment , we can conclude that:

m∠E = m∠Y

m∠F= m∠X

m∠G = m∠Z

∴ ΔEFG ~ ΔYXZ ( ΔEFG is similar to ΔYXZ )

Because of the similarity , then:

FE : XY = EG : YZ = GF : ZX

Conclusion:

ΔFG is similar to ΔYXZ.

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

3 0

3 years ago

Read 2 more answers

Evaulate 10^2 + 6 multiplied by 7 + 8

Alinara [238K]

Evaluating $10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8$ we get 1590

Step-by-step explanation:

We need to evaluate $10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8$

Solving:

$10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8\\=(10^2+6)\times(7+8)\\=(100+6)\times(15)\\=106\times15\\=1590$

So, evaluating $10^2 + 6 \,\,multiplied\,\, by\,\, 7 + 8$ we get 1590

Keywords: Solving the expressions

Learn more about Solving the expressions at:

#learnwithBrainly

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3 years ago

Does anyone know how to graph trigonometric functions for algebra 2?

anastassius [24]

Solution:

Give the following below

$\begin{gathered} amplitude=3 \\ period=\frac{\pi}{2} \\ midline,\text{ }y=-1 \\ Passing\text{ through the point }(0,2) \end{gathered}$

To find the cosine function, we will apply the general formula for cosine function below

$\begin{gathered} f(x)=a\cos(bx-c)+d \\ Where \\ a\text{ is the amplitude} \\ b\text{ represents the speed of the cycle} \\ d\text{ is the vertical shift} \\ \frac{c}{b}\text{ is the phase shift \lparen horizontal shift\rparen} \\ Period=\frac{2\pi}{b} \end{gathered}$

To find the value of b

$\begin{gathered} Period=\frac{\pi}{2} \\ \frac{2\pi}{b}=\frac{\pi}{2} \\ Crossmultiply \\ b\times\pi=2\times2\pi \\ b=\frac{4\pi}{\pi} \\ b=4 \end{gathered}$ $\begin{gathered} a=3 \\ b=4 \\ d=-1 \\ c=0 \end{gathered}$

Substitute the values of the variables into the general formula for cosine function

$\begin{gathered} f(x)=a\cos(bx-c)+d \\ f(x)=3\cos(4x-0)-1 \\ f(x)=3\cos4x-1 \end{gathered}$

Applying a graphing tool,

The graph of one cycle of the function is shown below

4 0

1 year ago