3 years ago

How do you write y=-4x^2-16x-14 in vertex form??

Mathematics

2 answers:

GREYUIT [131]3 years ago

8 0

y= -4x² - 16x - 14

Take the coefficient of x² as the common factor

y = - 4(x² + 4x + 7/2)

Add (b/2)² to complete the square

y = - 4( x² + 4x + 2² - 2² + 7/2)

Complete the square

y = -4( (x + 2)² - 1/2)

Remove the bracket

y = -4(x + 2)² + 2

Answer: y = -4(x + 2)² + 2

Juli2301 [7.4K]3 years ago

6 0

Answer:

y = -4(x + 2)² + 2

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What is the discriminant of 3 x squared minus 10 x = negative 2?

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$3x^2-10x+2=0$ ..........(1)

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