Expertsss/aceee plzzz helpppp quickkklyyyy (81% complete a couple more to go)

A histogram is better for _____________ data and a frequency polygon is better for ________data.

Ne4ueva [31]

A histogram is better for "discrete" data and a frequency polygon is better for "continuous" data.

<h3>What is histogram?</h3>

A histogram is a data representation that looks like a bar graph and buckets a wide range of categories into columns all along horizontal x-axis.

The numeric count or percentage of happenings in the data for every column is represented by the vertical y-axis.
Columns can be employed to visualize data distribution patterns.
Technical analysts use the MACD histogram in trading to making data in momentum.
The MACD histogram columns could provide buy and sell signals earlier than the MACD and signal lines.

<h3>What is frequency polygon?</h3>

Frequency polygons are a graphs depiction of the distribution that aids in data comprehension by utilizing a specific shape.

Frequency polygons are comparable to histograms but are more beneficial when comparing two or more different data sets.
The graph primarily displays cumulative frequency distribution data as a line graph.
Frequency Polygons are a type of graph that deciphers information or data and are broadly used in statistics.
This graphic form of data representation aids in the depiction of the data's shape and trend in a systematic and organized manner.

To know more about the histogram, here

brainly.com/question/2962546

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5 0

2 years ago

Which equation could be used to solve the problem? Sarah spent $160 on lunch in 10 weeks. If she spent the same amount every wee

ser-zykov [4K]

The correct answer would be A, because 160/10 is getting you your unit rate, or the amount Sarah spent every week.

6 0

3 years ago

Please help quick!!!!!!

Anvisha [2.4K]

Answer:

180 or 150

Step-by-step explanation:

good luck my friend

7 0

3 years ago

Read 2 more answers

Solve the given initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0, y(1) = 1

Yuri [45]

Let's check if the ODE is exact. To do that, we want to show that if

$\underbrace{(x+y)^2}_M\,\mathrm dx+\underbrace{(2xy+x^2-2)}_N\,\mathrm dy=0$

then $M_y=N_x$ . We have

$M_y=2(x+y)$
$N_x=2y+2x=2(x+y)$

so the equation is indeed exact. We're looking for a solution of the form $\Psi(x,y)=C$ . Computing the total differential yields the original ODE,

$\mathrm d\Psi=\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0$
$\implies\begin{cases}\Psi_x=(x+y)^2\\\Psi_y=2xy+x^2-2\end{cases}$

Integrate both sides of the first PDE with respect to $x$ ; then

$\displaystyle\int\Psi_x\,\mathrm dx=\int(x+y)^2\,\mathrm dx\implies\Psi(x,y)=\dfrac{(x+y)^3}3+f(y)$

where $f(y)$ is a function of $y$ alone. Differentiate this with respect to $y$ so that

$\Psi_y=2xy+x^2-2=(x+y)^2+f'(y)$
$\implies2xy+x^2-2=x^2+2xy+y^2+f'(y)$
$f'(y)=-2-y^2\implies f(y)=-2y-\dfrac{y^3}3+C$

So the solution to this ODE is

$\Psi(x,y)=\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3+C=C$

i.e.

$\dfrac{(x+y)^3}3-2y-\dfrac{y^3}3=C$

6 0

3 years ago

you buy a Lily and an African Violet on the same day you were instructed to water the Lily every 4th day and water The Violet ev

nexus9112 [7]

The Least Common Multiple (LCM) will calculate when they are watered on the same day.

LCM of 4 and 7 is 28.

Answer: They will be watered together every 28 days.

3 0

4 years ago