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Anarel [89]
2 years ago
7

A cyclist travels 15km due north and then 18 km due east. How far is she from the starting point?​

Mathematics
1 answer:
zavuch27 [327]2 years ago
8 0

Answer:

DONT KNOW SRY

Step-by-step explanation:

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Answer 10,11 and 12 for 100 points
geniusboy [140]
10) 7(2m+3)
11) 3(3r-1)
12) 2p(5q+4)
3 0
3 years ago
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Kayla get paid $15 to rake the lawn. Kayla get paid 3 times as much to rake the lawn as she does to mow the lawn. How much does
Xelga [282]

Answer :

15$  x   3  =  <em><u>45 </u></em>

Step-by-step explanation:

You just have to multiply the amount that kayla gets payed <em>(15$)</em> to the number of times that she mows the lawn <em>( 3 times )</em>.

<em>Then you do the eqaution which is :</em>

<u>15$  x   3   </u>  

<em>And that give you your answer which is:</em>

<u>45</u>                              :)

4 0
3 years ago
100 POINTS IF U GET THIS RIGHT!
Sloan [31]

Answer:

  • 5/6 km²  

Step-by-step explanation:

<u>Use the area equation:</u>

  • A = 1/2bh

<u>Substitute values:</u>

  • A = 1/2* 1 2/3 * 1 = 1/2*5/3 = 5/6 km²
4 0
3 years ago
A small airline overbooks flights on the assumption that several passengers will not show up. Suppose that the probability that
olchik [2.2K]

We have 22 tickets sold, and 20 seats. This means that at least 2 passengers must not show up (otherwise, at least 21 passengers will be present, and there wouldn't be space for them).

Considering each passenger as independent, you can think of this experiment. Suppose you toss a coin for each passenger. If the coin lands on heads, the passenger shows up. If it lands on tails, the passenger doesn't show up.

But the coin is unfair: it has a 0.91 probability of landing on heads, and thus 0.09 probability of landing on tails.

This implies that the probability of having exactly k tails is

\binom{22}{k} \cdot 0.09^k \cdot 0.91^{22-k}

We already concluded that at least two passengers must not show up. So, if our coins lands on tails less than twice, we've lost. So, the losing probability is

\displaystyle\binom{22}{0}\cdot 0.09^0 \cdot 0.91^{22} + \binom{22}{1}\cdot 0.09^1 \cdot 0.91^{21} \approx 0.39

Finally, remember the rule to negate events:

P(E) = 1-P(\lnot E)

So, if we lose with probability 0.39, we win with probability

1-0.39 = 0.61

6 0
3 years ago
How do you write -3( 1 - 8m - 2n) in standard form.
Ulleksa [173]

You distribute the three into the numbers in parentheses. -3+24n+6n. Then combine like terms. -3+30n


But I may be wrong.

7 0
3 years ago
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