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sesenic [268]
3 years ago
13

4x^2-y^2 how do you factorize this? with steps pls:)

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
<h3>Answer:  (2x-y)(2x+y)</h3>

===========================================

Work Shown:

4x^2 - y^2

(2x)^2 - (y)^2

(2x-y)(2x+y)

When going from the second step to the third step, I used the difference of squares rule. That rule is a^2-b^2 = (a-b)(a+b). In this case, a = 2x and b = y.

Side note: (2x-y)(2x+y) is the same as (2x+y)(2x-y). We can multiply in any order.

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Consider the function below, which has a relative minimum located at (-3 , -18) and a relative maximum located at (1/3, 14/17).
leonid [27]
First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27).  But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing.  The first derivative of the function is f'(x)=-3x^2-8x+3.  Set the derivative equal to 0 and factor to find the critical numbers. 0=-3x^2-8x+3, so x = -3 and x = 1/3.  We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing.  From there we will look at our points to determine which fall into the "decreasing" category.  Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞.  In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval.  In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval.  In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval.  In order to determine where our points in question fall, look to the x value.  The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12).  The point (-3, -18) is already a min value.
8 0
3 years ago
What is the answer ​
dybincka [34]

Answer:

C

Step-by-step explanation:

Just re-draw the triangle reflecting the y-axis

3 0
4 years ago
You want to test the claim that the average age of students at Gorka College is greater than the average age of students at Yapo
777dan777 [17]

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis :

H0 : μ1 = μ2

H1 : μ1 > μ2

Given :

x1 = 21.1 ; n1 = 53 ; s1 = 1.1

x2 = 20.7 ; n2 = 46 ; s2 = 1.2

The test statistic :

(x1 - x2) / √[(s1²/n1 + s2²/n2)]

(21.1 - 20.7) / √[(1.1²/53 + 1.2²/46)]

0.4 / 0.2326682

Test statistic = 1.719

The degree of freedom using the conservative method :

Comparing :

Degree of freedom = n - 1

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Smaller degree of freedom is chosen ;

The Pvalue from Test statistic, using df = 45

Pvalue = 0.0462

Pvalue < α ; Hence, there is significant evidence to conclude that average age of Gorka student is higher than Yaphoa.

7 0
3 years ago
Find the slope of the line.
Lera25 [3.4K]

Answer:

  = -3

Step-by-step explanation:

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We can use the slope formula

m = (y2-y1)/(x2-x1)

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Answer:

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Step-by-step explanation:

-5w from

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6 0
3 years ago
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