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Yakvenalex [24]
3 years ago
13

Whats the answer to 5-y=10

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
5-y=10 , 10-5=y, so y=5
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7/5 + 3/8 =what /40 + what/40 = ?/?
VARVARA [1.3K]

Answer:

71/40

Step-by-step explanation:

7/5*8/8=56/40+3/8*5/5= 15/40 so 15/40+56/40=71/40

6 0
4 years ago
How many kilograms of a 5% salt solution and how many kilograms of a 15% salt solution must be mixed together to make 45kg of an
JulsSmile [24]

Answer:

31.5 kilograms of a 5% salt solution and 13.5 kilograms of a 15% salt solution must be mixed together to make 45kg of an 8% salt solution .

Step-by-step explanation:

Let us assume that the number of kilograms of a 5% salt solution used be x .

Let us assume that the number of kilograms of a 15% salt solution used be y .

As given

A 5% salt solution and 15% salt solution must be mixed together to make 45kg of an 8% salt solution .

Equation becomes

x + y = 45

5% is written in the decimal form .

= \frac{5}{100}

= 0.05

15% is written in the decimal form .

= \frac{15}{100}

= 0.15

8% is written in the decimal form .

= \frac{8}{100}

= 0.08

Thus

Concentration of 5% salt solution × Number of kilograms of 5% salt solution used + Concentration of 15% salt solution × Number of kilograms of  15% solution used = Concentration of 8% salt solution × Number of kilograms of 8% salt solution

Thus

0.05x + 0.15y = 0.08 × 45

Simplify the above

\frac{5x}{100} + \frac{15y}{100} = \frac{8\times 45}{100}

5x + 15y = 360

Thus two equations becomes

x + y = 45

5x + 15y = 360

Multiply x + y = 45 by 5 and subtracted from 5x + 15y = 360 .

5x - 5x + 15y - 5y = 360 - 225

10y = 135

y = \frac{135}{10}

y = 13.5 kilograms

Put value of y in the equation

x + 13.5 = 45

x = 45 - 13.5

x = 31.5 kilograms

Therefore the 31.5 kilograms of a 5% salt solution and 13.5 kilograms of a 15% salt solution must be mixed together to make 45kg of an 8% salt solution .

5 0
3 years ago
Solve right triangle ABC given the following: C = 90° , B = 53°, b = 23.
Anastasy [175]
A=17.33174
c=28.79912
A=37
area=199.31505


pls give brainliest if someone else comments :)
7 0
3 years ago
Pleaseplease help me
Mars2501 [29]

Answer:

1,4

Step-by-step explanation:

The anwser is 1,4

4 0
3 years ago
Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°
umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

or

\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ

6 0
3 years ago
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