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user100 [1]
3 years ago
11

Line ef is tangent to circle g at point h. segment gh is a radius of circle g. what can be concluded about triangle fhg?

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

Right triangle

Step-by-step explanation:

It is given that the line ef is tangent to the circle g at the point h and the segment gh is the radius of the circle g.

Now, A line tangent to a circle is perpendicular to the radius to the point of tangency, thus making a right angle at the point h with the segment gh.

Therefore, the triangle FHG is a right triangle.

solong [7]3 years ago
3 0
We know that

A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
<span>Line ef is </span>perpendicular to the segment gh

hence
Triangle FHG is a right triangle
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\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{\quad  k}})\qquad &#10;radius=&{{ r}}\\&#10;&-3&-1&5&#10;\end{array} &#10;\\\\\\\&#10;[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
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