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WARRIOR [948]
2 years ago
14

A napkin has an area of 5 square inch. what is the side length of the napkin

Mathematics
1 answer:
shutvik [7]2 years ago
4 0
To find<span> the width, multiply the </span>length<span> that you have been given by 2, and subtract the result from the perimeter. You now have the total </span>length<span> for the remaining 2 </span>sides<span>. This number divided by 2 is the width.</span>
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It cost Evan $17.70 to send 177 text messages. How many text messages did he send if he spent $19.10?​
rusak2 [61]

Answer:

191

Step-by-step explanation:

The amount spent for a single text:  177/17,7=0,1

x×0,1=19,1

x=19,1/0,1

x=191

6 0
2 years ago
What is the slope and y-intercept of this line?
garik1379 [7]

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How do you solve 2i and 2ii​
natta225 [31]

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15 and 21

Step-by-step explanation:

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T = 2n + 5

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3 years ago
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Step-by-step explanation:

6 0
2 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin4t,sin7t,9t⟩,r(0)=⟨9,8,3⟩
Makovka662 [10]
\mathbf r'(t)=\langle\sin4t,\sin7t,9t\rangle
\implies\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt
\mathbf r(t)=\displaystyle\left\langle\int\sin4t\,\mathrm dt,\int\sin7t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle
\mathbf r(t)=\left\langle-\dfrac14\cos4t+C_1,-\dfrac17\cos7t+C_2,-\dfrac92t^2+C_3\right\rangle

With \mathbf r(0)=\langle9,8,3\rangle, we have

\langle9,8,3\rangle=\left\langle-\dfrac14+C_1,-\dfrac17+C_2,C_3\right\rangle
\implies C_1=\dfrac{37}4,C_2=\dfrac{57}7,C_3=8
\implies\mathbf r(t)=\left\langle-\dfrac14\cos4t+\dfrac{37}4,-\dfrac17\cos7t+\dfrac{57}7,-\dfrac92t^2+8\right\rangle
6 0
3 years ago
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