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shepuryov [24]
2 years ago
10

If f(x) = (x+1)-1 and g(x) = x–2, what is the domain of Rx) = g(x)?

Mathematics
1 answer:
german2 years ago
3 0

Step-by-step explanation:

f is (x+1)-1

and g (the next letter in the alphabet) is x-2

first for f

x+1-1 = x

Then we -2 for g

So every letter there o words is just 2 less than the previous letter like

h would be h= x-4

so r(x) is g which is x-2 and x which would have to be the remaining amount to get to the number

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Find the value of x. please explain your answer:)
marshall27 [118]

Answer:

x=16

Step-by-step explanation:

we know that 3x+2=50 according to complemntary  angles.

3x=48

x=16


5 0
3 years ago
Need help asap!!!
antiseptic1488 [7]

Answer:

there is no solution

Step-by-step explanation:

y + 7 = 3x

6x - 2y = 6    which can be simplied to be 3x - y = 6  (divide by 2)

let y = 3x - 7

substitute:  3x -(3x - 7) = 6

                  3x - 3x + 7 = 6

                              7 ≠ 6  therefore, no solution

8 0
3 years ago
Which of the following represents the relationship between the circumference, c, and diameter, d, of any circle?
Usimov [2.4K]

Given:

Circumference of a circle = C

Diameter of a circle = d

To find:

The relationship between the circumference, c, and diameter, d, of any circle.

Solution:

We know that, circumference of a circle is

C=2\pi r

It can be written as

C=(2r)\pi

C=d\pi         [\because d=2r]

On dividing both sides by d, we get

\dfrac{C}{d}=\pi

Therefore, the correct option is (F).

6 0
2 years ago
Am i correct pls help
a_sh-v [17]

Answer:

yea ur correct

Step-by-step explanation:

use PhotoMath or something like that to check next time, it'll save a lot of time

6 0
3 years ago
Evaluating integral by net area
N76 [4]

The graph of f(x)=2 is a horizontal line. So the area under f(x) on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of g(x)=\sqrt{64-x^2} is the upper half of a circle with radius \sqrt{64}=8. It's symmetric about x=0, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is \frac{\pi 8^2}4=16\pi.

Then use the fact that the definite integral is distributive over sums, meaning

\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi

8 0
3 years ago
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