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____ [38]
3 years ago
12

List the two factors that affect ionic bond

Chemistry
1 answer:
drek231 [11]3 years ago
8 0
Ionization energy and electron affinity
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Heat that flows by conduction is the transfer of thermal energy between substances in contact. What must occur for this to happe
rodikova [14]

Answer:

Heat is transferred from the warmer block to the cooler block

Explanation:

Heat transfer by conduction involves two or more solids. The heat generally moves from a part at higher temperature to one with a lower temperature.

  • Heat transfer is based on the differences in temperature profile on a body.
  • When the temperature of the body is the same, heat is not transferred.
  • The molecules that makes up the hotter body collides with static molecules of the cold one.
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What is a taste threshold test?
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The basic tastes of sweet, salty and sour have different thresholds, or concentration levels, at which they can be detected. In other words, it is easier to detect some flavors at low concentrations compared with other flavors. Taste thresholds can vary from person to person.

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3 years ago
If a fish tank holds 6912 cubic inches of water, how many cubic feet of water are there in a fish tank.
stiv31 [10]

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The answer is 576

Explanation:

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6 0
2 years ago
Organelles → tissues → organs → organ systems → organism
Viefleur [7K]
A is the correct answer cells between organelles and tissues
3 0
4 years ago
Read 2 more answers
An unknown gas has a pressure of 699.0 mm Hg at 40.0 C. What is the temperature at standard pressure?
Anit [1.1K]

Hello!

An unknown gas has a pressure of 699.0 mm Hg at 40.0 C. What is the temperature at standard pressure ?

We have the following information:

P1 (initial pressure) = 699 mmHg

T1 (initial temperature) = 40 ºC (in Kelvin)

TK = TºC + 273.15 → TK = 40 + 273.15 → T1 (initial temperature) = 313.15 K

P2 (final pressure) = 1 atm (in STP) → P2 (final pressure) = 760 mmHg

T2 (final temperature) = ? (in Kelvin)

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, then we will have the following formula:

\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}

\dfrac{699}{313.15} = \dfrac{760}{T_2}

699*T_2 = 760*313.15

699\:T_2 = 237994

T_2 = \dfrac{237994}{699}

T_2 = 340.4778255... \to \boxed{\boxed{T_2 \approx 340\:K}}\end{array}}\qquad\checkmark

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

7 0
3 years ago
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