C
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Explanation:
The energy of a wave is given by the formula;
E= hf
Whereby;
E = energy
h = Plank’s constant
f = frequency
Remember that f can be also represented as;
¹/ λ
Whereby;
λ = wavelength
Wavelength and frequency are therefore inversely proportional.
Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.
Learn More:
For more on frequency and wavelength of waves check out;
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First, calculate the number of moles of sodium present with the given mass,
31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium
It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.
mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2
Then, at STP, 1 mol of gas = 22.4 L.
volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L
Answer: 15.34 L
the modern atomic model shows that electrons are located in a predicted area but cannot be identified in a specific point
Hope this helps :)
Answer:
Aspartic acid may be considered hydrophobic at physiological.
Answer:
The three major types of bond are ionic, polar covalent, and covalent bonds. Ionic occurs majorly between metals and non-metals, which allows sharing of electrons to form an ionic compound. Whereas covalent bonding calls for complete transfer of electrons between atoms. Polar covalent bonds have unequaly shared electron-pair between two atoms.
Explanation:
a. Cu (Copper)-<em> ionic bonding
</em>
b. KCl (Potassium Chloride)
- <em>ionic bonding
</em>
c. Si (Silicon)
- <em>covalent bonding
</em>
d. CdTe (Cadmium Telluride)
- <em>polar covalent bonding
</em>
e. ZnTe (Zinc Telluride)- <em>polar covalent bonding
</em>
