Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>
Explanation:
Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.
Answer:
1.77 * 10^-3
Explanation:
From the titration formula;
Let
CA = concentration of acid
CB = concentration of base
VA = volume of acid
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
The equation of the reaction is;
M(OH)2(aq) + 2HCl(aq) -------> MCl2(aq) + 2H2O(l)
So;
CAVA/CBVB= NA/NB
CAVANB = CBVBNA
CB= CAVANB/VBNA
CB= 0.173 * 25.10 * 1/28.5 * 2
CB= 4.3423/57
CB= 0.0762 M
This implies that the solubility of M(OH)2 = 0.0762 M
M(OH)2(s) ----> M^+(aq) + 2OH^-(aq)
So
Ksp = x * (2x)^2
Ksp = 4x^3
x = 0.0762
Ksp= 4(0.0762)^3
Ksp = 1.77 * 10^-3