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Mumz [18]
3 years ago
6

Can you help me with 5.025- 5.030?

Chemistry
1 answer:
goblinko [34]3 years ago
3 0
I am not sure about .030 but i would pick c
.025) b
26)c
27)d
28)d
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A 20 ml sample of .875 m hcl solution was diluted t o150 ml. calculate the molarity of the resulting solution
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0.11666667 because M1V1=M2V2
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What is a control group used for?
jeka94
  • The control group defined as  a group that does not include any change to the inconstant being tested. Why is a control crucial in an experiment? The control group is crucial because it acts as a benchmark to variatethe results of the experiment to. The experimental group is the group that the scientist is examing . The experimental group receives a change to a variable, or the conditions allowed to change in the experiment.
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3 0
10 months ago
Balance the equation and show the calculation of the number of moles and grams of CO2 formed from 11.9 grams of O2. Show your an
n200080 [17]

Answer:

0.2349 moles, 10.3356 g

Explanation:

The given reaction is :

C_6H_{14}+O_2\rightarrow CO_2 + H_2O

The balanced reaction by equating the same number of each atom both side is :

2C_6H_{14}+19O_2\rightarrow 12CO_2 + 14H_2O

Given that :

Amount of oxygen gas = 11.9 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles are:

moles= \frac{11.9\ g}{32\ g/mol}

moles= 0.3719\ mol

From the reaction,  

19 moles of oxygen gas on reaction forms 12 moles of carbon dioxide

Also,

1 mole of oxygen gas on reaction forms 12/19 moles of carbon dioxide

So,

0.3719 moles of zinc on reaction forms \frac {12}{19}\times 0.3719 mole of carbon dioxide

<u>Moles of carbon dioxide formed = 0.2349 moles</u>

Mass of carbon dioxide = moles×Molar mass

Molar mass of carbon dioxide = 44 g/mol

<u>Mass of carbon dioxide formed = 0.2349 ×44 g = 10.3356 g</u>

4 0
3 years ago
A phospholipid/(s) that is a/ are abundant in egg yolk is/are?
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So, the correct answer will be C) Lecithin

3 0
3 years ago
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