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Mumz [18]
4 years ago
6

Can you help me with 5.025- 5.030?

Chemistry
1 answer:
goblinko [34]4 years ago
3 0
I am not sure about .030 but i would pick c
.025) b
26)c
27)d
28)d
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The ----------------- cells, make up the upper and lower layers of the leaf.
Nataly [62]

Answer:

epidermal! hope this helps u!

4 0
3 years ago
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A student must use 220 mL of hot water in a lab procedure. Calculate the amount of heat required to raise the temperature of 220
Inessa [10]

Answer:

64,433.6 Joules

Explanation:

<u>We are given</u>;

  • Volume of water as 220 mL
  • Initial temperature as 30°C
  • Final temperature as 100°C
  • Specific heat capacity of water as 4.184 J/g°C

We are required to calculate the amount of heat required to raise the temperature.

  • We know that amount of heat is calculated by;

Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

    = 70°C

Therefore;

Amount of heat, Q = 220g × 4.184 J/g°C × 70°C

                               = 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules

7 0
3 years ago
Your teacher drinks a glass of water in the front of the classroom and claims, “this water could have been frozen in a glacier o
Anit [1.1K]

Answer:

Through the processes of melting of the glacier to form water, evaporation of water, condensation and precipitation, water in the form of melting glaciers in Greenland could have moved to the Loch Raven Reservoir and on to our school's water fountain.

Explanation:

Considering a glacier in Greenland. When this glacier melts, its waters flows into the ocean. Subsequent heating of the ocean by sun causes the water to evaporate and rise into the sky as water vapor. This water vapor cools on rising and then condenses into water droplets in sky which forming clouds. A cloud is made of water drops or ice crystals floating in the sky.

Wind movement would then carry the clouds over great distances. These water droplets within a cloud will condense onto one another, causing the droplets to grow. When these water droplets become too heavy to remain suspended in the cloud, they will then either precipitate as rain or snow on land, rivers and oceans.

Over time, with continuous cycling and repetition of these processes, water melting from a glacier in Greenland will eventually make its way into the  Big Gunpowder Falls river which feeds the Loch Raven Reservoir in Baltimore and subsequently, the water will be supplied to our school's water fountain.

6 0
3 years ago
How much power is used if a force of 54 newtons is used to pull a wagon a distance of 10 meters in 6 seconds? 3,240 W 90 W 32.4
timama [110]
Power is defined in a mathematical expression as P = F x v where F is in N and v is in m/s. From the given equation, the v = d/t which is v = 10/ 6, then substituting the answer to the power formula W = 54 N (10/6 m/s) = 90 Watts. 
3 0
3 years ago
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Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following
bearhunter [10]

Answer:

210.7~g~MgCO_3

Explanation:

We have to start with the <u>reaction</u>:

MgCO_3~->~MgO~+~CO_2

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:

(12*1)+(16*2)=44~g/mol

In other words: 1~mol~CO_2=~44~g~CO_2. With this in mind, we can calculate the moles:

110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2

Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:

2.5~mol~CO_2=2.5~mol~MgCO_3

With the molar mass of MgCO_3 ((23.3*1)+(12*1)+(16*3)=84.3~g/mol. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:

2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3

I hope it helps!

8 0
3 years ago
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