Answer:
its corresponding to the wrong one
solution:
we are consider the following function,
f(x)=3x+k,x\leq 3
=kx^{2}-6,x>3
\lim_{x\rightarrow 3^-}(3x+k)=9+k
\lim_{x\rightarrow3^+}
(kx^{2}-6)=9k-6
so the left and right limits are equal.
therefore, the function is continuous at x=3
so,the therom of the function is continous at x=3
9k-6=9+k
8k=15
k=15/8
=1.875
therefore,the value of k=1.875
Answer:
Line a is parallel with line b
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
4 is the base of the equation and then as it goes on, you add 2* the point in the sequence -1
1.) -15.9, -15.2, -3.6, 3.6
2.) second one is already correct
3.)-2.3, -2.03, 2.03, 3.0
