Given:
The graph of function g(x) is a transformation of the graph of function f(x) = x²
As shown: the graph of g(x) is open down
So, we will reflect f(x) over the x-axis, the function will be ⇒ -x²
And there is horizontal compression so, the factor of compression will be > 1
So, the function will be ⇒ -2x²
Finally, there is a vertical shift down 3 units
So,
Answer:
about 16°
Step-by-step explanation:
Make sure your calculator is in degree mode.
Drawing the right triangle, we see that the shorter leg is 34 meters, and the longer leg is 122 meters. So the angle of elevation is:
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Answer: 4x^2 -13x + 14
Step-by-step explanation:
(x^2 - 8x + 5)-(-3x^2 + 5x-9)
Subtract -3x^2 from x^2
(4x^2 - 8x + 5)-(5x-9)
Subtract 5x from -8x
(4x^2 -13x + 5)-(-9)
Subtract 9 from 5
4x^2 -13x + 14
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
Answer:
Step-by-step explanation:
<u><em>b).</em></u>
2x² - 9x - 5 = ( x - 5 )( 2x + 1 )
3x² - 15x = 3x ( x - 5 )
=