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Luba_88 [7]
3 years ago
8

In a study conducted to examine the quality of fish after 7 days in ice​ storage, ten raw fish of the same kind and approximatel

y the same size were caught and prepared for ice storage. The fish were placed in ice storage at different times after being caught. A measure of fish quality was given to each fish after 7 days in ice storage. Review the accompanying sample data and​ scatterplot, where​ "Time" is the number of hours after being caught that the fish was placed in ice storage and​ "Fish Quality" is the measure given to each fish after 7 days in ice storage​ (higher numbers mean better​ quality). Is it appropriate to use the correlation coefficient to describe the strength of the relationship between​ "Time" and​ "Fish Quality"?

Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0

Question: The sample data and the scatter plot was not added to your question. See the attached file for the scatter plot.

Answer: Yes

Step-by-step explanation:

From scatter plot, it was discovered that there is a linear relationship between the two variables and both variables are quantitative.

Therefore, it appropriate to use the correlation coefficient to describe the strength of the relationship between​ "Time" and​ "Fish Quality"?

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suppose you deposit $1000 in a savings account that pays 4.8% interest compounded monthly. Write an exponential function to mode
zubka84 [21]

Answer:

The exponential function is A(t) = 1000(1.004)^{12t}.

You will have $1,100.55 in the account after 2 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Deposit $1000 in a savings account that pays 4.8% interest compounded monthly.

This means that P = 1000, r = 0.048, n = 12. So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 1000(1 + \frac{0.048}{12})^{12t}

A(t) = 1000(1 + 0.004)^{12t}

A(t) = 1000(1.004)^{12t}

This is the exponential function

How much will you have in your account after 2 years?

This is A(2). So

A(2) = 1000(1.004)^{24} = 1100.55

You will have $1,100.55 in the account after 2 years.

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Spencer??
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