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3 years ago

I WILL GIVE 50 POINTS ON THE NEXT QUESTION TO WHOMEVER ANSWERS THIS CORRECT

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

6 0

It is a function because no two points cross the x-axis. It passes the vertical line test.

anastassius [24]3 years ago

5 0

How do you want me to draw the line , but answer yes this is a function because if I draw any vertical line it intersects once because it has 1 input and 1output but if the graph intersects more than once it is not a function

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Write an expression that is equivalent to 4(b+2)-3b

vekshin1

Ok so first we need to distribute so:
=(4)(b)+(4)(2)+−3b
=4b+8+−3b
So now that we've distrubuted that we are now going to Combine Like Terms:
=4b+8+−3b
=(4b+−3b)+(8)
Finally your answer is:
=b+8
I hope this helps you!

6 0

3 years ago

Read 2 more answers

ASAP PLEASE HELP!! 50 POINTS

svetlana [45]

Answer/Step-by-step explanation:

Total Distance = 3Ft

a) Determine the amplitude and period of a sinusoidal function that models the bobbing buoy.

Amplitude = 3/2 = 1.5 period = 10 second

$\frac{0}{1} =\frac{2\pi }{b}$ $b=\frac{\pi }{5}$ No ph. Shift

b) Write an equation of a function that models the buoy with x=0 at its highest point.

y= 1.5 cos ( $\frac{\pi }{5} x$ )

3 0

2 years ago

When is the product of two nonzero integers less than or equal to both of the two factors

Sergeu [11.5K]

1) if they're both 1:

1 x 1 = 1: they preoduct is equal to both factors!

2) if one of them is negative (but not 2!)

for example: -2 and 6: the product is -12, and it's less than both -2 and 6!!!

5 0

3 years ago

Simplify the expression 2(10)+2(x-2)

FrozenT [24]

Answer:

16 + 2x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$