What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)
1 answer:
Answer:
Perimeter = 6x² + 8x
Step-by-step explanation:
Perimeter = 2(length + width)
perimeter = 2((x²+x)+(2x²+3x))
perimeter = 2(x²+2x² + x+3x)
perimeter = 2(3x² + 4x)
perimeter = 2*3x² + 2*4x
perimeter = 6x² + 8x
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