What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)
1 answer:
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Intercept form is: y = a(x - p)(x - q)
It is given that: p = 14, q = -6, x = 14, y = 4
4 = a(14 - 12)(14 - (-6))
4 = a(2)(20)
4 = 40a
Answer: y = (x - 14)(x + 6)
Answer:
<u>Step-by-step explanation:</u>
When you subtract b/2a from both sides, you end up with the Quadratic Formula.