3 years ago

What is the perimeter of a rectangle with a length of (x^2+x) and a width of (2x^2+3x)

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

Perimeter = 6x² + 8x

Step-by-step explanation:

Perimeter = 2(length + width)

perimeter = 2((x²+x)+(2x²+3x))

perimeter = 2(x²+2x² + x+3x)

perimeter = 2(3x² + 4x)

perimeter = 2*3x² + 2*4x

perimeter = 6x² + 8x

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