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aleksklad [387]
2 years ago
13

For each set of three measures, determine if they can be angle measures of a triangle

Mathematics
1 answer:
Readme [11.4K]2 years ago
6 0

Answer:

Sum of all three angles =170

∘-180

Step-by-step explanation:

Solution

Correct option is

C

65

∘

,85

∘

,30

∘

Given set (A) 70

∘

,90

∘

,25

∘

Sum of all three angles =185

∘

>180

∘

This set cannot form a triangle

(B) 65

∘

,85

∘

,40

∘

Sum of all three angles =190

∘

>180

∘

This set cannot form a triangle

(C) 65,85

∘

,30

∘

Sum of all three angles =180

∘

This set can form a triangle

(D) 45

∘

,45

∘

,80

∘

Sum of all three angles =170

∘

<180

∘

This set cannot form a triangle

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Step-by-step explanation:

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Tom's weekly salary increased from $240 to $288. What was the percent of change?
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Answer:

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Find the factors of f(x), given that x = −2 is a zero. HELP PLEASE!!
seropon [69]

Answer:

First Option is correct.

(x+2)(x+3)(x-4)

Step-by-step explanation:

Given:

The given factor is.

f(x)=x^{3}+x^{2}-14x-24

We need to find the factors of given factor.

Solution:

f(x)=x^{3}+x^{2}-14x-24

Substitute (-4x-10x) in the place of -14x

f(x)=x^{3}+x^{2}-4x-10x-24

Rearrange the equation:

f(x)=(x^{3}-4x)+(x^{2}-10x-24)

Now we factorised the above equation.

The factors of x^{2} -10x-24=(x+2)(x-12)

Now we substitute (x+2)(x-12) in the place of x^{2} -10x-24

And in the place of x^{3}-4x=x(x^{2}-4)

f(x)=x(x^{2}-4)+(x+2)(x-12)

Simplify x^{2} -4=x^{2} -(2)^{2} = (x+2)(x-2)

f(x)=x[(x+2)(x-2)]+(x+2)(x-12)

Common factor for above function (x+2)

f(x)=(x+2)[x(x-2)+(x-12)]

Simplify.

f(x)=(x+2)[x^{2}-2x+x-12]

f(x)=(x+2)(x^{2}-x-12)

The factor of x^{2}-x-12=x^{2}-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)

So the factors of the function.

f(x)=(x+2)(x-4)(x+3)

Therefore, the factors of the given function are (x+2)(x-4)(x+3)

4 0
3 years ago
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7 0
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