Since the intersection is - by definition - common to both sets, we can work out the number of people that use only the fitness suite or the swimming pool.
We know that 57 people use the fitness suite, but 36 of those are already counted in the intersection. So, 57-36=21 people use only the fitness suite.
The same goes for the swimming pool: 49-36=13 people use only the swimming pool.
So, we have:
- 21 people using fitness suite only
- 13 people using swimmng pool only
- 36 people using both
This sums to 21+13+36=70 people. We deduce that 30 people don't use any of the features.
Answer:
Option D will be correct.
Step-by-step explanation:
The 333 erasers cost $4.41.
We have to determine the cost of 444 erasers.
Let the price of 444 erasers is $x.
Therefore, since the number of erasers cost per dollars is constant, hence the equation that would help to determine the cost of 444 erasers will be 
⇒ 
Therefore, option D will be correct. (Answer)
Answer:
(x - 1)² + (y + 1/2)² = 65/4
Step-by-step explanation:
Given: the endpoints of the diameter are (3, 3) and (-1, -4). a( To determine the center of this circle, find the midpoint of the line segment connecting these two points:
3 - 1
x = -----------
2
and
-1
y = ----------
2
The center is at x = 1 and y = -1/2: (1, -1/2).
b) The radius is half the diameter. The diameter is the distance between the two endpoints given, that is, the distance between (-1, -4) and (3, 3):
diameter = √(4² + 7²) = √(16 + 49) = √65; therefore,
radius = (1/2)√65.
square of the radius = r² = 65/4
The general equation of a circle with center at (h, k) and radius r is
(x - h)² + (y - k)² = r². In this case, the equation is:
(x - 1)² + (y + 1/2)² = 65/4
Answer:
a range of values such that the probability is C % that a rndomly selected data value is in that range
Step-by-step explanation:
complete question is:
Select the proper interpretation of a confidence interval for a mean at a confidence level of C % .
a range of values produced by a method such that C % of confidence intervals produced the same way contain the sample mean
a range of values such that the probability is C % that a randomly selected data value is in that range
a range of values that contains C % of the sample data in a very large number of samples of the same size
a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time
a range of values such that the probability is C % that the population mean is in that range
