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tangare [24]
3 years ago
14

Is the difference of two positive rational number always positive explain

Mathematics
1 answer:
Dominik [7]3 years ago
5 0
No . . . while the difference represents the absolute magnitude between two numbers . . . for example . . .

<em>The difference between 5 and 2 is . . . 3</em>
<em>The difference between 6.4 and 9.5 is . . . 3.1</em>

 . . . there is still the chance that the difference may be zero . . . in which case the difference is neither positive nor negative

. . . so in short . . . the answer is . . . <u><em>NO</em></u>

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Someone please help me on this question
Rudik [331]
100 + 10x=15x. Subtract 10x from both sides. 100=5x. Divide by 5 on both sides. x=20. So you would need to buy 20 movies. 
7 0
3 years ago
Determine whether each given value of x satisfies the inequality x+1&lt;x/3
Vinil7 [7]

x+1 < \dfrac{x}{3}\ \ \ \ |\cdot3\\\\3x+3 < x\ \ \ \ |-3\\\\3x < x-3\ \ \ \ |-x\\\\2x < -3\ \ \ \ |:2\\\\x < -1.5

Answer: (c) x = -4

5 0
3 years ago
PLEASE SHOW YOUR WORK.
schepotkina [342]

Answer:

a) Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7

b) The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as

98 square feet

Step-by-step explanation:

The area in, square feet, of Shawn’s garden is found be calculating 15(2x + 7). Shawn incorrectly says the area can also be found using the expression 30x + 7.

The correct area =

15(2x + 7).

= 30x + 105 square feet

The error in Shawn’s expression is

= 15(2x + 7)

= 30x + 7 square feet

Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7

The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as

30x + 105 square feet - 30x + 7 square feet

= 30x + 105 - (30x + 7)

= 30x - 30x + 105 - 7

= 98 square feet

7 0
3 years ago
What the recursive formula for the sequence
klemol [59]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})


so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}


just a quick note on notation:

\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}

8 0
3 years ago
If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?
yuradex [85]
Y
y=ax
where a is a constant of proportionality;
y=20, x=4
20=4a
a=20/4
a=5
y=5x
The constant of variation is 5
3 0
3 years ago
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