PLEAASE HELP I HAVE LITERALLY NO TIME LEFT I WILL GIVE BRAINLY SOON PLS HELP

50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Nataliya [291]

<h3>Answer: 9</h3>

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Work Shown:

Apply the pythagorean theorem

a^2 + b^2 = c^2

12^2 + b^2 = 15^2

144 + b^2 = 225

b^2 = 225-144

b^2 = 81

b = sqrt(81)

b = 9

5 0

3 years ago

Read 2 more answers

You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m

Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

h = 0.9 m

k = 1500 $\frac{N}{m}$

Since the book is released from a height h = 0.9 m above the top of the spring. so the total distance

y = h + x

Now in that case for the spring

$mg y= \frac{1}{2} k x^{2}$

$mg(h +x) = \frac{1}{2} k x^{2}$

By rearranging the above equation we get

$k x^{2} - 2mgx - 2mg h = 0$

Put all the values in above equation we get

$1500x^{2} - 29.43 x - 26.48 = 0$

By solving the above equation we get

x = 0.143 m= 14.3 cm

This is the value of the maximum distance the spring will be compressed.

8 0

3 years ago

Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta

DaniilM [7]

Answer:

2½ h

Step-by-step explanation:

Assume the graph is like the one below.

The graph shows how Erin's distance varies with time.

To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.

From there, draw a horizontal line until it hits the graph.

Then drop a vertical line to the horizontal axis.

It hits half-way between 2 and 3.

It takes Erin 2½ h to run 25 mi.

7 0

3 years ago

Read 2 more answers

Which of the following is NOT a linear factor of the polynomial function?

Natalija [7]

Answer:

Among the four choices, $(x + 5)$ is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let $a$ denote some constant. A linear factor of the form $(x - a)$ is a factor of a polynomial $f(x)$ if and only if $f(a) = 0$ (that is: replacing all $x$ in the polynomial $f(x) \!$ with the constant $a\!$ would give this polynomial a value of $0$ .)

For example, in the second linear factor $(x - 2)$ , the value of the constant is $a = 2$ . Verify that the value of $f(2)$ is indeed $0$ . (In other words, replacing all $x$ in the polynomial $f(x) \!$ with the constant $2$ should give this polynomial a value of $0\!$ .)

$\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}$ .

Hence, $(x - 2)$ is indeed a linear factor of polynomial $f(x)$ .

Similarly, it could be verified that $(x - 5)$ and $(x + 2)$ are also linear factors of this polynomial function.

Rewrite the first linear factor $(x + 5)$ in the form $(x - a)$ for some constant $a$ : $(x + 5) = (x - (-5))$ , where $a = -5$ .

Calculate the value of $f(5)$ .

$\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}$ .

$f(5) \ne 0$ implies that $(x - (-5))$ (which is equivalent to $(x + 5)$ ) isn't a linear factor of this polynomial function.

3 0

3 years ago

Use the interactive graph to plot each set of points. Which sets represent proportional relationships? Check all that apply.

dem82 [27]

Answer:

The table C is a linear functionFor a function to be a linear function, then the x and the y values must change at a constant rates.From the question, as the x values of table C constantly change by 1, the y values constantly change by -2This means that the table C is a linear function

Step-by-step explanation:

8 0

2 years ago