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il63 [147K]
3 years ago
10

Classifying Rational Numbers Write each rational number in the form a/b, where a and b are integers. 2 7/8

Mathematics
2 answers:
GaryK [48]3 years ago
7 0

Answer:

I have no clue and I was wondering some questions also

Zinaida [17]3 years ago
6 0

Answer:

0.25 Irrational (?) used math celebrity for calc

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What is the value of x?<br> 21<br> 24<br> 32<br> 44
Mumz [18]

Answer:

21

Step-by-step explanation:

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3 0
3 years ago
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Find what h equals please help ASAP THANK YOU!<br><br> 4h-1=3h+2
Sunny_sXe [5.5K]
H = 3.

FIRST STEP:
<span>Add 1 to both sides to get rid of the -1 on the left side.
4h-1 = 3h+2
</span><span>4h-1 (+1) = 3h+2 (+1)
</span><span>4h = 3h+3
 
SECOND (FINAL) STEP:
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h = 3
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3 0
3 years ago
Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)
masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

y=ax^2+bx+c            ...(i)

It is passes through the point (0,11). So, substitute x=0,y=11 in (i).

11=a(0)^2+b(0)+c

11=c

Putting c=11 in (i), we get

y=ax^2+bx+11               ...(ii)

The quadratic function passes through the point (5,31). So, substitute x=5,y=31 in (ii).

31=a(5)^2+b(5)+11

31-11=a(25)+5b

20=25a+5b

Divide both sides by 5.

4=5a+b                  ...(iii)

The quadratic function passes through the point (3,11). So, substitute x=3,y=11 in (ii).

11=a(3)^2+b(3)+11

11-11=a(9)+3b

0=9a+3b

Divide both sides by 3.

0=3a+b                 ...(iv)

Subtracting (iv) from (iii), we get

4-0=5a+b-3a-b

4=2a

\dfrac{4}{2}=a

2=a

Putting a=2 in (iv), we get

0=3(2)+b

0=6+b

-6=b

Putting a=2,b=-6 in (ii), we get

y=(2)x^2+(-6)x+11

y=2x^2-6x+11

Therefore, the required quadratic equation is y=2x^2-6x+11.

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Answer:

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