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3 years ago

1.9996 by 2 significant numbers

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

8 0

1.9 or rounding with 2.0

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The function h (x) = StartFraction 1 Over x squared + 1 EndFraction is the result of the composition f(g(x)). If g(x) = x2 + 1,

dem82 [27]

Answer: 1/x

Step-by-step explanation:

7 0

3 years ago

Solve the equation for x. the square root of the quantity x minus 8 end quantity plus 2 equals 7 x = 1 x = 13 x = 17 x = 33

Masteriza [31]

The solution of the equation (√x-8) + 2 = 7 is x = 13.

According to the given question.

We have an equation

$\sqrt{x - 8} + 2 = 7x$

Since, we solve the above equation for x .

Therefore,

$\sqrt{x - 8} + 2 = 7$

⇒ (√x - 8) = 7 - 2

⇒ (√x - 8) = 5

Squarring both the sides.

⇒ x - 8 = 5

⇒ x = 5 + 8

⇒ x = 13

Hence, the solution of the equation (√x-8) + 2 = 7 is x = 13.

Find out more information about equation here:

brainly.com/question/15707224

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6 0

1 year ago

A METRIC UNIT OF MASS THAT IS EQUAL TO 1/1000 OF A GRAM IS CALLED A

Natali5045456 [20]

Milligram is your answer!!!

5 0

3 years ago

Read 2 more answers

5 in

Ugo [173]

Step-by-step explanation:

for such regular figures the volume is always

ground area × height.

the volume of the green box (bar on a rectangle) at the bottom is therefore

16×7×3 = 336 in³

the volume of the red object on top (based on a right-angled triangle) we get

5×3/2 × 6 = 5×3×3 = 45 in³

so, the total volume is the sum of both sub-volumes :

336 + 45 = 381 in³

5 0

3 years ago

Let f(x)=⌊x/2⌋. We learned that the floor and the ceiling functions are NOT invertible, but we also learned about the set of pre

romanna [79]

Answer:

Value of $f^{-1}(\{4\})$ is 8.

Step-by-step explanation:

Given function,

$f(x)=\big[\frac{x}{2}\big]$

we have to find : $f^{-1}(\{4\})$

It is known that,

$[x]$ =the greatest integer <=x

Then,

$f(x)=\big[\frac{x}{2}\big]$

$\implies x=f^{-1}(\big[\frac{x}{2}\big])$

Taking x=8 we get,

$f^{-1}(\big[\frac{x}{2}\big])=x$

$\implies f^{-1}(\big[\frac{8}{2}\big])=8$

$\implies f^{-1}([4])=8$

$\implies f^{-1}(\{4\})=8$ ( Since [4]=4 )

Hence the value of $f^{-1}(\{4\})$ is 8.

7 0

3 years ago