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svp [43]
3 years ago
14

a store is selling bags of potting soil for $1.79 each. there is $.60 mail-in rebate on each bag of soil bought. what are the po

ssible numbers of bags of potting soil you can buy if you spend no more than $15?
Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:about 6 bags

Step-by-step explanation:

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Find the value of y.<br> Iog 2 32 =y<br> Ο<br> Ο<br> OC. 6<br> Ο<br> D.<br> 7
Delicious77 [7]

Answer:

B 5

Step-by-step explanation:

log 2(32)

Replace 32 with 2^5

log2 (2^5)

We know that log a^b = bloga

5 log2(2)

We know that loga(a) =1

5*1

5

6 0
3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
How many woods are there
nikitadnepr [17]
6 wooden sticks and one long wooden border
so totally 7 wood is there
I think this correct 
3 0
3 years ago
Solve the equation and check the solution4.4x-4=3.4x
PolarNik [594]
4.4x-4=3.4x

Substract '-3.4x' at LHS nad the RHS of the above expression.

\begin{gathered} 4.4x-4-3.4x=3.4x-3.4x \\ 4.4x-3.4x-4=0 \\ x-4=0 \end{gathered}

Add '4' on both LHS and RHs of the above expression.

undefined

4 0
1 year ago
Solve this problem on paper using all four steps. A girl scout troop sold cookies. If the girls sold 5 more boxes the second wee
Varvara68 [4.7K]
This is a problem where you should make an equation.
Let's say x is the first week. It would mean
First Week : x
Second Week : x + 5
Third Week : 2(x+5)
You need to add these up to make your equation. Your equation will look something like this :
x+x+5+2(x+5) = 431
Now you simplify.
2x+5+2x+10 = 431
4x+15 = 431
4x = 416
x = 104
That means they sold 104 Boxes in the First Week.
104+5=109
So they sold 109 Boxes the Second Week.
109 x 2 = 218
And they sold 218 Boxes the Third Week.

I hope I was useful!
3 0
3 years ago
Read 2 more answers
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