Answer:
90
Explanation:
take note that V= (velocity is distance over (divided by) time. so in this case its 198(distance) divided by 2.2 (time) =90
Answer:
the correct one is C
Explanation:
For this exercise we must use the work definition
W = F. s
Where the bold characters indicate vectors and the point is the scalar producer
W = F s cos θ
Where θ is the angles between force and displacement.
Let us support this in our case. The cable creates an upward tension and with the elevator going down the angle between them is 180º so the work of the cable on the elevator is negative.
The evade has a downward force, its weight so the force goes down and the displacement goes down, as both are in the same direction the work is positive
When examining the statements the correct one is C
We are given
m = mass of the object
r = distance from the center of the planet
r <span>≥ rplanet
We are asked for the
ve = escape velocity
The escape velocity
ve = </span>√ (2Gm/r)
<span>
</span>
The magnitude of the average force that the ball exerts against his glove is 600 N
<h3>Further explanation</h3>
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
<u>Given:</u>
mass of ball = m = 0.15 kg
initial speed of ball = u = 40 m/s
final speed of ball = v = 0 m/s
distance = d = 20 cm = 0.2 m
<u>Asked:</u>
average force = F = ?
<u>Solution:</u>
<em>We will use </em><em>Newton's Law of Motion</em><em> to solve this problem as follows:</em>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics
Answer:
The speed at the end of the track = 27 m/s
The acceleration = 1.2 m/s²
Please find the Δx vs Δt, v vs Δt, a vs Δt
Explanation:
We have;
x = u·t + 1/2·a·t²
Where;
x = The distance = 300 m
u = The initial velocity = 0 m/s (Ball at rest)
t = The time taken = 22.4 s
Therefore;
300 = 0 + 1/2×a×22.4²
a = 2×300/22.4² = 1.19579 ≈ 1.2 m/s²
v = u + a×t
∴ v = 0 + 1.2 × 22.4 = 26.88 ≈ 27 m/s
Part of the table of values is as follows;
t, x, v
0, 0, 0
0.4, 0.095663, 0.478316
0.8, 0.382653, 0.956632
1.2, 0.860969, 1.434948
1.6, 1.530611, 1.913264
2, 2.39158, 2.39158
2.4, 3.443875, 2.869896
2.8, 4.687497, 3.348212
3.2, 6.122445, 3.826528
3.6, 7.748719, 4.304844