Hello there hey what time is it where you live right now?

Correct displacement 4km south,2 km north, 5km south, and 5 km north

babymother [125]

Answer:

2 km due south.

Explanation:

We need to find the displacement of 4km south,2 km north, 5km south, and 5 km north.

Let south is negative direction and north is positive direction.

The shortest path covered by an object is called its displacement.

D = -4+2-5+5

D = -2 km

So, the displacement is 2 km and it is in south direction.

8 0

3 years ago

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s afte

Arturiano [62]

Answer:

a) a = 2.35 m/s^2

Explanation:

(a) In order to calculate the magnitude of the acceleration of the ball, you use the following formula, for the position of the ball:

$x=v_ot+\frac{1}{2}at^2$ (1)

x: position of the ball after t seconds = 87 m

t: time = 8.6 s

a: acceleration of the ball = ?

vo: initial velocity of the ball = 0 m/s

You solve the equation (1) for a:

$x=0+\frac{1}{2}at^2\\\\a=\frac{2x}{t^2}$

You replace the values of the parameters in the previous equation:

$a=\frac{2(87m)}{(8.6s)^2}=2.35\frac{m}{s^2}$

The acceleration of the ball is 2.35 m/s^2

6 0

3 years ago

The step by step experiment to determine the cubic expansivity of a liquid

Anit [1.1K]

In accordance with the definition of density as r = m/V, in order to determine the density of matter, the mass and the volume of the sample must be known. The determination of mass can be performed directly using a weighing instrument. The determination of volume generally cannot be performed directly. Exceptions to this rule include · cases where the accuracy is not required to be very high, and · measurements performed on geometric bodies, such as cubes, cuboids or cylinders, the volume of which can easily be determined from dimensions such as length, height and diameter. · The volume of a liquid can be measured in a graduated cylinder or in a pipette; the volume of solids can be determined by immersing the sample in a cylinder filled with water and then measuring the rise in the water level. Because of the difficulty of determining volume with precision, especially when the sample has a highly irregular shape, a "detour" is often taken when determining the density, by making use of the Archimedean Principle, which describes the relation between forces (or masses), volumes and densities of solid samples immersed in liquid: From everyday experience, everyone is familiar with the effect that an object or body appears to be lighter than in air – just like your own body in a swimming pool. Figure 3: The force exerted by a body on a spring scale in air (left) and in water (right)

7 0

3 years ago

A 2kg box is pushed along a flat frictionless surface with an applied force of 53.91newton j+19.62 j were j is horizontal and j

tamaranim1 [39]

Since the box doesn't move vertically at all, no work is done by the vertical component of the force.

If 53.91 Newtons is the horizontal component of the force (very unclear in the question), then the work done is

Work = (force) x (distance)

Work = (53.91 N) x (10 m)

Work = 539.1 Joules

Power = (work done) / (time to do the work)

Power = (539.1 joules) / (90 sec)

Power = (539.1/90) (joule/sec)

Power = 5.99 watts

=====================================

Note: If the mass of the box is only 2 kg, and you push it along the surface with a constant force of 53⁺ Newtons, and the surface really is frictionless, then that box is gonna cover a WHOOOOOLE LOT more than 10 meters in 90 seconds. I get 109,168 meters !

5 0

4 years ago

Studen

Vesna [10]

Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

a

From this motion what is the distance covered

b

What is the magnitude and direction of the displacement

Answer:

a

$D = 72 \ m$

b

Magnitude

$d = - 20 \ m$

Direction

West

Explanation:

From the question we are told that

The first distance covered westward is $d_w_1 = 18 \ m /tex] The first distance covered eastward is [tex]d_e1 = 12 \ m /tex] The second distance covered westward is [tex]d_w_2 = 28 \ m /tex] The second distance covered eastward is [tex]d_e2 = 14 \ m /tex] Generally the distance covered is mathematically represented as [tex]D = d_w1 + d_w2 + d_e1 + d_e2$

=> $D = 18 + 28 + 12 + 14$

=> $D = 72 \ m$

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

$d = -d_w1 -d_w2 + d_e1 + d_e2$

=> $d = -18-28 + 12 + 14$

=> $d = - 20 \ m$

The direction is west

7 0

3 years ago

Hello therehey what time is it where you live right now?​

Hello therehey what time is it where you live right now?