Answer:
T = 27.92 N
Explanation:
For this exercise let's use Newton's second law
T - W = m a
The weight
W = mg
The acceleration can be found by derivatives
a = dv / dt
v = 2 t + 0.6 t²
a = 2 + 0.6 t
We replace
T - mg = m (2 + 0.6t)
T = m (g + 2 + 0.6 t) (1)
Let's look for the time for the speed of 15 m / s
15 = 2 t + 0.6 t²
0.6 t² + 2 t - 15 = 0
We solve the second degree equation
t = [-2 ±√(4 - 4 0.6 (-15))] / 2 0.6
t = [-2 ±√40] / 1.3 = [-2 ± 6.325] / 1.2
We take the positive time
t = 3.6 s
Let's calculate from equation 1
T = 2.00 (9.8 + 2 + 0. 6 3.6)
T = 27.92 N
Answer:
I THINK it would be False.
Energy at top = U = mgh = 40 * 9.8 * 12 = 4704 J
Energy at bottom = 1/2 mv² = 1/2 * 40 * 10² = 4000 / 2 = 2000 J
Energy Lost = Final - Initial = 4704 - 2000 = 2704 J
In short, Your Answer would be 2704 Joules
Hope this helps!
<h2>Answer </h2>
Option C - Carbon Dioxide and Water
<u>Explanation </u>
The chemical equation reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O).
CH4 + 2O2 → CO2 + 2H2O.
In this equation, carbon dioxide and water are products. Products are substances which are formed after a chemical reaction so in this case carbon dioxide and water are formed as a result after a chemical reaction. Therefore, these are products of reaction of methane and oxygen gas.