Answer:
P = 17.28*10⁶ N
Explanation:
Given
L = 250 mm = 0.25 m
a = 0.54 m
b = 0.40 m
E = 95 GPa = 95*10⁹ Pa
σmax = 80 MPa = 80*10⁶ Pa
ΔL = 0.12%*L = 0.0012*0.25 m = 3*10⁻⁴ m
We get A as follows:
A = a*b = (0.54 m)*(0.40 m) = 0.216 m²
then, we apply the formula
ΔL = P*L/(A*E) ⇒ P = ΔL*A*E/L
⇒ P = (3*10⁻⁴ m)*(0.216 m²)*(95*10⁹ Pa)/(0.25 m)
⇒ P = 24624000 N = 24.624*10⁶ N
Now we can use the equation
σ = P/A
⇒ σ = (24624000 N)/(0.216 m²) = 114000000 Pa = 114 MPa > 80 MPa
So σ > σmax we use σmax
⇒ P = σmax*A = (80*10⁶ Pa)*(0.216 m²) = 17280000 N = 17.28*10⁶ N
<em>why Is there just a random "u" in the middle of the equation </em><em>awa</em><em> </em>
<em> </em><em>t</em><em>h</em><em>e</em><em>question is impossible to do btw </em>
<em>Imao the u in the middle doesn't makes sense </em>
if<em> you edit the question I'll help you w it)</em>
have a good day bro cya
Answer:
= 33.33 cm
Explanation:
Given:
When mass, 
=21 kg
distance travelled is 
= 140 cm
When mass, 
=5 kg
distance travelled is = ?
Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.
Therefore according to the question,
= 33.33 cm
Distance travelled is 33.33 cm when mass is 5 kg.
