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4 years ago

Fill in the following information for the element cesium

Chemistry

2 answers:

zzz [600]4 years ago

5 0

Answer:

Explanation:

period:soft metal

group: caesius

family: Alkali

hope this helps i really tried on this one i do know its the

softest metal it basically wax at room temperature

pretty cool

Nutka1998 [239]4 years ago

5 0

Period : 6
Group: 1
Family: alkali

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Please help!

Anna71 [15]

The compound that is most likely present when treated with bromine and the sample absorbs the red bromine color is ; Cycloheptene

<h3>What is cycloheptene </h3>

Cycloheptene is an unsaturated colorless oily liquid which is insoluble in water it absorbs Bromine when used in performing unsaturation test due it unsaturated nature.

The red bromine color will be absorbed when used to treat Cycloheptene but will not be absorbed when used to treat cycloheptane due to its saturated nature.

Hence we can conclude that the compound that is present is Cycloheptene.

Learn more about Unsaturation : brainly.com/question/561845

5 0

3 years ago

How many Mg 2+ ions are present in 3.00 moles of MgCl2

Nostrana [21]

This is what I got hope this makes sense:There is 1 mol of Mg 2+ ions in one mole of MgCl2, we can get that from the formula.
Multiply 3.00 moles by 6.022x10^23 to get moles of MgCl2.
There are 6.022x10^23 ions in one mole of substance.
(3.00)(6.022x10^23)
=1.81x10^24 Mg 2+ ions
Hope it helps though

6 0

3 years ago

Chemicals are classified as health hazards when they pose which of the following hazardous effects?

AlexFokin [52]

Answer:

poisoning, breathing problems, skin rashes, allergic reactions, allergic sensitisation, cancer, and other health problems from exposure.

Explanation:

many hazardous chemicals are also classified as dangerous goods.

4 0

3 years ago

True or false: A flower's only function is for reproduction

lapo4ka [179]

The answer is false. Hope this helps

3 0

3 years ago

Read 2 more answers

Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at

ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

$4Al+3O_2\rightarrow 2Al_2O_3$

From the balanced reaction we conclude that

As, 3 mole of $O_2$ react with 4 mole of $Al$

So, 0.188 moles of $O_2$ react with $\frac{4}{3}\times 0.188=0.251$ moles of $Al$

From this we conclude that, $Al$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$

From the reaction, we conclude that

As, 3 mole of $O_2$ react to give 2 mole of $Al_2O_3$

So, 0.188 moles of $O_2$ react to give $\frac{2}{3}\times 0.188=0.125$ moles of $Al_2O_3$

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of $Al_2O_3$ releases amount of heat = 1676 kJ

So, 0.125 mole of $Al_2O_3$ releases amount of heat = $0.125\times 1676kJ=209.5kJ$

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0

3 years ago