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4 years ago

Fill in the following information for the element cesium

Chemistry

2 answers:

zzz [600]4 years ago

5 0

Answer:

Explanation:

period:soft metal

group: caesius

family: Alkali

hope this helps i really tried on this one i do know its the

softest metal it basically wax at room temperature

pretty cool

Nutka1998 [239]4 years ago

5 0

Period : 6
Group: 1
Family: alkali

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Energy flows from the plankton to a number of other organisms when the plankton are eaten. Describe how the decrease in plankton

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Less plankton would mean that all the organisms that eat plankton would start to die off because they have no source of energy.

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3 years ago

Isotonic saline solution, which has the same osmotic pressure as blood, can be prepared by dissolving 0.923 g of nacl in enough

vova2212 [387]

<span>osmotic pressure = CRT to get C, get the number of moles of NaCl then divide it with volume of the solution mole NaCl = 0.923g / 58.442 g/mol mole NaCl = 0.0158 mol C = 0.0158 mol / 0.1L C = 0.158 mol/L So, osmotic pressure = 0.158 mol/L*(0.082058 L-atm/mol-K)*(25+273K) osmotic pressure = 3.86 atm</span>

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4 years ago

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Balanced Chemical Equation: 2H2(g)+O2(g)——> 2H2O(g)

Tcecarenko [31]

You must use 134 g O₂ to produce 118 g H₂O.

$\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \%$

$\text{Theoretical yield} = \text{Actual yield}\times \frac{100\%}{\%\text{ yield}} = \text{118 g }\times \frac{100 \%}{78.2 \%} = \text{150.9 g}$

M_r: 32.00 18.02

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Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O

Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂

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4 years ago

Four flasks each contain 100 milliliters of aqueous solutions of equal concentrations at 25°C and 1 atm.

KonstantinChe [14]

Answer:

KCl and Ba(OH)₂.

Explanation:

Hello there!

In this case, since electrolytes are substances characterized by presence of covalent bonds between the atoms forming the compound, it is possible to realize that just KCl and Ba(OH)₂ as they are species composed by cations (K and Ba) and anions (OH and Cl); therefore, they have the capacity to get ionized in aqueous solution and thus transfer electricity when present.

Best regards!

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3 years ago

The acid-dissociation constant, ka, for gallic acid is 4.57 ⋅ 10-3. what is the base-dissociation constant, kb, for the gallate

LiRa [457]

Hello!

To determine the Kb of gallic acid is actually very simple.

The dissociation reaction of Gallic Acid (HGal) is the following:

HGal+H₂O ⇄ H₃O⁺ + Gal⁻

The equation for converting from Ka to Kb is the following:

$Ka*Kb=Kw \\ \\ Kb= \frac{Kw}{Ka}= \frac{1*10^{-14} }{4,57*10^{-3} }=2,19 * 10^{-12}$

So, the Kb is 2,19*10⁻¹²

Have a nice day!

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3 years ago

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