Explanation:
H3PO4 is a weak acid so it partially dissociates in water
Ka1
H3PO4 (aq) + H2O(l) <----> H2PO4-(aq) + H3O+ (aq)
Ka2
H2PO4- (aq) + H2O(l) <----> HPO4 2- (aq) + H3O+ (aq)
Ka3
HPO4 2- (aq) + H2O(l) < ---> PO4 3- (aq) + H3O+ (aq)
Answer:
The molarity of the chromium(III) acetate solution 0.3982 M.
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
Explanation:

Mass of chromium(III) acetate = 22.8 g
Molar mass of chromium(III) acetate = 229 g/mol
Total volume of the solution of chromium(III) acetate = V = 250 mL = 0.250 L
1 mL = 0.001 L
The molarity of the chromium(III) acetate solution :
![[Cr(CH_3COO)_3]=\frac{22.8 g}{229 g/mol\times 0.250 L}=0.3982 M](https://tex.z-dn.net/?f=%5BCr%28CH_3COO%29_3%5D%3D%5Cfrac%7B22.8%20g%7D%7B229%20g%2Fmol%5Ctimes%200.250%20L%7D%3D0.3982%20M)
The molarity of the chromium(III) acetate solution 0.3982 M.

According to reaction, 1 mole of chromium(III) acetate gives 1 mole of chromium(III) ions and 3 moles of acetate ions.
So ![[Cr^{3+}]=[Cr(CH_3COO)_3]=0.3982 M](https://tex.z-dn.net/?f=%5BCr%5E%7B3%2B%7D%5D%3D%5BCr%28CH_3COO%29_3%5D%3D0.3982%20M)
![[CH_3COO^-]=3\times [Cr(CH_3COO)_3]=3\times 0.3892 M=1.1946 M](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D3%5Ctimes%20%5BCr%28CH_3COO%29_3%5D%3D3%5Ctimes%200.3892%20M%3D1.1946%20M)
0.3982 M is the concentration of the chromium(III) cation.
1.1946 M is the concentration of the acetate anion.
Cesium because it is the only one that belongs to the alkali group.
Answer:
1 hour of heat to regenerate all the excemulayed water
Answer:
Strong acids react faster where as weak acids take time to react with any base.