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zepelin [54]
4 years ago
13

8 blocks can build a house. Jimmy has 165 blocks, how many houses can he build? How many blocks will he have left?​

Mathematics
1 answer:
noname [10]4 years ago
3 0

Answer:

He can build 20 houses. He will have 5 left over.

Step-by-step explanation:

8 x 20 = 160

165 (total blocks) - 160 (highest possibility) = 5 (not enough to build a house, which is why they are left over)

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One major discrepancy I'm noticing is in the values you found for \ln\sin\theta. For example, if \sin\theta=0.05, then you should have \ln\sin\theta=\ln0.05\approx=-3.0. Not sure how you got -7.0, and the same goes for the rest of your table of values.

Another thing is that the provided solution suggests you take the average the first and last pairs of consecutive data points, and use these values in the slope formula to obtain the best-fit line's slope. If that's the case, then you should have

\dfrac{\Delta\ln x}{\Delta\ln\sin\theta}=\dfrac{\frac{1.86+1.72}2-\frac{2.65+2.28}2}{\frac{-5.4-5.3}2-\frac{-7.0-6.4}2}=\dfrac{1.79-2.47}{-5.35+6.7}=\dfrac{-0.68}{1.35}\approx-0.5

(i.e. you have to take the average of the given values, then use those averages in the \Delta expressions - but this doesn't significantly affect the slope you found)

Ultimately, I think the problem is that your expression for the slope appears to be \dfrac{\Delta\ln x}{\Delta\ln\sin\theta}, when the solution says it should be the reciprocal. I'm of the opinion that your slope is correct, since the experiment refers to \theta (and hence \sin\theta) as the independent variable, and so \Delta\ln\sin\theta would serve as the "run" and \Delta\ln x would serve as the "rise".

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Step-by-step explanation:

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