Answer:
y = w/4x+1
Step-by-step explanation:
The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² =
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
Volume of octagon =
Therefore, the pool can hold 65.84 ft³ of water
28
35% × 80 =
(35 ÷ 100) × 80 =
(35 × 80) ÷ 100 =
2,800 ÷ 100 =
I hope this helps :)
1.068.
Use the identity
sec^2 O = 1 + tan^2 O
= 1 + (3/8)^2
= 1 9/64
= 73/64
so sec O = √73/8
= 1 .068.
A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z