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Svetlanka [38]
3 years ago
9

2, 4, 13, 49, 193,

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

If we begin with the first term, 2, mult. it by 4 and then subtract 3, we get 5 (not 4, as shown).

If we begin with 4, mult. it by 4 and then subtract 3, we get 13. This agrees with the terms of the given sequence.

If we begin with 13, mult. it by 4 and then subtract 3, we get 49. This agrees with the terms of the given sequence.

Remove the first term, 2, and then the remaining terms follow the given procedure for finding terms.


AlekseyPX3 years ago
3 0
2 because if you multiply by 4,then subtract 3,you get 5 not 13.
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Lady bird [3.3K]

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12\sqrt{2}

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\sqrt{12^2+12^2}

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4 0
3 years ago
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7 0
2 years ago
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Lelechka [254]

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g(x) = 15

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6 0
3 years ago
Graph y &lt; x2 + 4x. Click on the graph until the correct graph appears.
jonny [76]

Answer:  The correct answer is:  

_________________________  

The given "graph" in the bottom right, lowest corner

Step-by-step explanation:

_________________________

Note:  When there is only one (1) equation give for a graph;

          and/or:  only one (1)  "inequality given";  

         we  look for the symbol.

If the symbol is "not" an "equals" symbol (i.e. not an:  =  symbol) ;

 we check for the type of "inequality" symbol.

If there is a:  "less than" (<) ;  or a "greater than" (>) symbol;  the graph of the "inequality" will have "dashed lines" (since there will be a "boundary").

If there is an "inequality" that is a: "less than or equal to" (≤) ;

                                                 or a: "greater than or equal to" (≥) ;

       →   then there will be not be a dashed line when graphed;

          but rather—a "solid line" ;  since "less than or equal to" ;

          or "greater than or equal to" —is similar to:

          "up to AND including"; or: "lesser/fewer than AND including".).

 _________________________  

Note:  We are given the "inequality" :

            →   " y <  x²  + 4x  "  .

_________________________________

Note that we have a "less than" symbol (< ) ; so the graph will have a:

   "solid line" [and not a "dotted line".].

_________________________________

Note that all of the graphs among our 4 answer choices have "dotted lines".

Not that all values (all x and y coordinated) within the "shaded portion" of the corresponding graph are considered part of the graph.  

As such, given any point within the shaded part,  the x and y coordinates must match the inequality (i.e. the given inequality must be true when one puts in the "x-coordinate" and "y-coordinate" into the "given inequality" :

→   " y <  x²  + 4x "  .

_________________________

Likewise, we can take any point within the "white, unshaded" portion of any of the graph, and take the "x-coordinate" and "y-coordinate" of that point, and the inequality: →   " y <  x²  + 4x  "  ;  will not hold true when the "x-coordinate" and "y-coordinate" values of that point— are substituted into the "inequality".  

_________________________

{Note:  Answer is continued on images attached.}.

Wishing you the best!

6 0
2 years ago
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kirill [66]

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D

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therefore,area of shaded portion= area of 3 circle =118.72

7 0
2 years ago
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