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3 years ago

5

Find the area of the shaded figure in the diagram below. Use 3.14 for π and round your answer to the nearest hundredth.

1 answer:

kirill [66]3 years ago

7 0

Answer:

D

Step-by-step explanation:

diameter of 1 circle = 21.3/3= 7.1

radius of 1 circle= 7.1/3=3.55

area of 1 circle =πr^2=3.14× (3.55)^2=39.57

area of 3 circle= 39.57×3=118.72

therefore,area of shaded portion= area of 3 circle =118.72

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10-x=-2x what is it ???

aniked [119]

Answer:

x = - 10

Step-by-step explanation:

Given

10 - x = - 2x ( add 2x to both sides )

10 + x = 0 ( subtract 10 from both sides )

x = - 10

4 0

3 years ago

Can anyone solve this for me?? I will give brainliest and 5 stars and thanks

Tcecarenko [31]

Answer:

3 cm

Step-by-step explanation:

When we enlarge or shrink an object, we perform a dilation. A dilation preserves the relationship between sides and the exact angle measure. This means the original and the enlargement are proportional and any missing lengths can be found through a proportion.

A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare height over length of the original rectangle to an equal ratio of height to length of the enlargement. Since we do not know height of the enlargement, we will use a variable to write:

$\frac{2}{9} =\frac{h}{13.5}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$9h=2(23.5)\\19h=27$

I now solve for h by dividing by 9.

$\frac{9h}{9} =\frac{27}{9} \\h= 3$

The new height is 3 cm.

5 0

3 years ago

AWSER PLASE IM STUCK ON THIS

dolphi86 [110]

1) 4 2/5 +1/5 = D)4 3/5
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3 0

3 years ago

Read 2 more answers

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

A movie rental kiosk charges a $25 membership fee and $3 per movie. An online movie service charges a $20 membership fee and $4

mylen [45]

25+3m=20+4m
25=20+m
5=m

7 0

3 years ago