Answer:
B. The allele frequency of T is 0.84, and the allele frequency of t is 0.16.
Explanation:
The Hardy-Weinberg equation is:
p2 + 2pq + q2 = 1
Where:
p = the frequency of the dominant allele
q = the frequency of the recessive allele
1 = the total number of alleles
Given that 16 individuals out of 100 are unable to taste PTC, we can calculate that the frequency of the recessive allele, q, is 0.16. We can then use the Hardy-Weinberg equation to solve for the frequency of the dominant allele, p:
p2 + 2pq + q2 = 1
p2 + 2p(0.16) + (0.16)2 = 1
p2 + 0.32p + 0.0256 = 1
p2 + 0.32p - 0.9144 = 0
(p + 0.32)(p - 2.84) = 0
p = -0.32 or p = 2.84
Since the allele frequencies must add up to 1, we know that p cannot equal -0.32. This leaves us with p = 2.84. Therefore, the allele frequency of the dominant allele is 2.84, and the allele frequency of the recessive allele is 0.16.
Answer:
Species 1(A): D F H I K
Species 2(B): L E
Species 3(C): G J
Explanation: the biological species concept defines a species as a group of populations whose members have the potential to interbreed in nature and produce viable, fertile offspring. This means that all members of these populations (called conspecifics) can contribute to a common gene pool. Conspecifics are organisms or populations that belong to the same species. Genes are transferred between conspecific populations through both direct and indirect gene flow.
Answer:
Africa needs to urgently put a number of additional measures in place to speed up these advances, and to move towards eliminating the disease. These include accelerated investment and deployment of vaccines, new diagnostic tools, new funding strategies for malaria control and keeping in check the drug and insecticide resistance challenge.
Explanation:
It is a perfect example of a natural selection.
(I'm not sure if this is the exact answer that you are looking for.)
